 | Abel Flint - Geometry - 1835 - 368 pages
...5' 0.47076. 105x85=8925, and 8925x0.47076=4201 the double area. pf the triangle. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, or the sum of the two parallel sides by half the perpendicular distance, the product will be the area.... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...breadth of the rectangle is «qual to half the sum of tha two parallel sides. RULE. — Multiply half the sum of the two parallel sides, by the perpendicular distance between them. All the figures we have considered, have been referred either to a square or to a rectangle. The area... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...10 chains ; what is the area? Ans., 24 chains. To find the area of a trapczoid. ROLE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 1. What is the area of a piece of land that is 30 chains long, 20 chains... | |
 | Commissioners of National Education in Ireland - Measurement - 1837 - 284 pages
...; required its area. Am. 700.99. PROBLEM XIII. To find the area of a Trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will give the area.* 1. Let ABCD be a trapezoid, the side AB=40, DC = 25, CP = 18, required... | |
 | George Willson - Arithmetic - 1838 - 194 pages
...of the rectangle is equal to naif the sum of the two parallel sides. . ... . RULE. — Multiply half the sum of the two parallel sides, by the perpendicular distance between them. All the figures we have considered, have been referred either to a square or to a rectangle. The area... | |
 | Charles Guilford Burnham - Arithmetic - 1841 - 324 pages
...chains. What is the area ? Answer, 24 chains. To fold the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 1. What is the area of a piece of land that, is 30 chains long, 20 chains... | |
 | Chambers W. and R., ltd - 1842 - 744 pages
...comprised within the quadrilateral. The area of a trapezoid is generally found by multiplying half the sum of the two parallel sides by the perpendicular distance between them ; the area of a trapezium may likewise be found in the same way. When it is desired to ascertain the... | |
 | J. M. Scribner - Measurement - 1844 - 130 pages
...chains and 130,27 chains 1 Am. 3207 A. 2 R. PROBLEM IV. To find the area of a Trapezoid. ' ART. 12. Rule. — Multiply the sum of the two parallel sides...between them, and half the product will be the area. Ex. 1. Required the area of the trape- D c zoid ABCD, having given .45=321.51 feet, DC=2 14.24 feet,... | |
 | Charles Haynes Haswell - Engineering - 1844 - 298 pages
...the Area of a, Trapezoid — fig. 9. RULE. — Multiply the sum of the parallel sides a 4, dc, by ah, the perpendicular distance between them, and half the product will be the area. OF REGULAR POLYGONS. RULE. — Multiply half the perimeter of the figure by the perpendicular, falling... | |
 | Thomas Tate (mathematical master.) - 1848 - 284 pages
...parallelogram AFGD. Application of this Theorem. From this theorem we derive the following rule for finding the area of a trapezoid. RULE. Multiply the sum of the...between them, and half the product will be the area of the trapezoid. Ex. 1. Required the area of a trapezoid ABCD, when AB = 6 ft., DC = 4 ft., and the... | |
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Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. 
