 | Jeremiah Day - Geometry - 1851 - 418 pages
...referred to. 94. Other relations of the sine, tangent, &c., may be derived from the proposition, that the square of the hypothenuse is equal to the sum of the squares of the perpendicular sides. (Euc. 47. 1.) In the right angled triangles CBG, CAD, and CHP,... | |
 | William Smyth - Algebra - 1851 - 272 pages
...the other two sides ? NOTE. In solving this and other similar questions, it will be recollected that the square of the hypothenuse is equal to the sum of the squares of the other two sides, and the area is equal to one half the product of these sideS. ANS.... | |
 | Edward Deering Mansfield - Education - 1851 - 348 pages
...in the year five hundred and ninety before Christ, who discovered the fundamental proposition that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Euclid appeared in the year three hundred BC His object was to systematize... | |
 | Horace Mann - 1851 - 384 pages
...lines 10ft. apart. This mode of operation is founded on the property of right-angled triangles, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. A roof is said to have a true pitch, when the length of each rafter... | |
 | Thomas Kentish - Geometrical drawing - 1852 - 258 pages
...29, and raise a perpendicular BC = 17. Join AB; apply it to the scale, and it will be found 33.6. For the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular. It is required to find the diameter of a copper, that, being... | |
 | Adolfo de Castro y Rossi - 1853 - 290 pages
...triangle rectangle;' " or with an Englishman who reads the same thing in his own language thus : " ' The square of the hypothenuse is equal to the sum of the squares of the two other sides of a rectangle triangle! " Thirdly, those who read in a well-known tongue,... | |
 | Benjamin Greenleaf - 1854 - 342 pages
...the perpendicular, the side AC the hypothenuse, and the angle at B is a right angle. Base. ART. 272. In every right angled triangle the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular, as shown by the following diagram. It will be seen by examining... | |
 | George Ticknor Curtis - Patent laws and legislation - 1854 - 718 pages
...applicable, are truths of exact science ; as the well-known propositions of geometry, that, in a right-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the opposite sides ; that the angle at the centre of a circle is double the angle at the... | |
 | Thomas Lund - Geometry - 1854 - 520 pages
...OBS. It is to be observed that the proposition proved in (43, Part I.), viz. that in any right-angled triangle the square of the hypothenuse is equal to the sum of the squares of the sides bounding the right angle, is of continual application in Mensuration, and enables... | |
 | Thomas Kentish - Mathematical instruments - 1854 - 268 pages
...29, and raise a perpendicular BC = 17. Join AB; apply it to the scale, and it will be found 33.6. For the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular. It- is required to find the diameter of a copper, that, being... | |
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The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302. 
