| George Albert Wentworth - Algebra - 1890 - 376 pages
...=am-\-an-\-ap-\-bm-\-bn-\-bp-\-cm-\-cn-}-cp. To find the product of two polynomials, therefore, Multiply every ierrn **of the multiplicand by each term of the multiplier, and add the partial products.** 69. In multiplying polynomials, it is a convenient arrangement to write the multiplier under the multiplicand,... | |
| George Albert Wentworth - Algebra - 1891 - 380 pages
...-(-p) + с ( w + i = am+aи4- ap4-6 That is, to find the product of two polynomials, ' Multiply every **term of the multiplicand by each term of the multiplier, and add the partial products.** 69. In multiplying polynomials, it is a convenient arrangement to write the multiplier under the multiplicand,... | |
| George Albert Wentworth - Algebra - 1891 - 550 pages
...ap + 6m + bn + ¿p + сw + cn + cp. That is, to find the product of two polynomials, Multiply every **term of the multiplicand by each term of the multiplier, and add the partial products.** 64, In multiplying polynomials, it is a convenient arrangement to write the multiplier under the multiplicand,... | |
| William James Milne - Algebra - 1892 - 370 pages
...-5a* — 5aж 3a2*3" 35. 36. 37. 38. Multiply 2 иs" By 4а*-ÏS :45Í? 3aГ i -5ж*+3 MULTIPLICATION. **RULE. — Multiply each term of the multiplicand by...and add the partial products. 2. 3. Multiply ab + 2c** 3 ж2 - (m/ By 2ab — 3c -3а&с-6с2 Product, 2a2b2+ а&с-6с2 Multiply : 4. x + y by x — y. 5.... | |
| George W. Lilley - Algebra - 1892 - 420 pages
...i5 +10 1» -5z -25 i10 + 2 z» -г 7 г« -«i4-3x" - 15x8+ 10x2-5;r- ¿5 Explanation. Multiplying **each term of the multiplicand by each term of the multiplier and** connecting these results with their proper signs, we have г10 - r' + 2x* - з* - 5 x* + 3 i» - ЗА... | |
| William James Milne - Algebra - 1894 - 216 pages
...a + 6 a + 6 a times a + 6 = a2 + a6 6 times a + b = a6 + 62 (a + 6) times (a + 6) = a2 + 2 a6 + 62 **RULE. Multiply each term of the multiplicand by each...of the multiplier, and add the partial products. 2.** 2 а6 - 3 с 4а6 + c 8a2f>2-12a6c 2 aЬc - 3 с2 8a262- 10 a6c -3с2 Multiply : 4. x + у by x + у.... | |
| William James Milne - Algebra - 1894 - 212 pages
...b a + b a times a + b = a1 + a6 b times a + b = a6 + 62 (a + 6) times (а + ft) = а2 4- 2 a6 + ft* **RULE. Multiply each term of the multiplicand by each...term of the multiplier, and add the partial products.** Z. 3. 2 a6 - 3 r ж3 - 3 x*y + Я ;ryi - у3 4 ab + rx — у 8a!b'- 12 abc x4 - 3 x3i/ + 3 tfy* -... | |
| William James Milne - Algebra - 1894 - 214 pages
...a + 6 а times a + b = a2 + ab b times a + b = ab + b1 (a + 6) times (a + 6) = a2 + 2 ab + 62 BULE. **Multiply each term of the multiplicand by each term...of the multiplier, and add the partial products. 2.** 2a6-3c 4 ab + с 8 a262- 12aftc 2 a6c - Я с2 8cW- 10 a6c -3с3 Multiply : 4. x + у by x + у. 5.... | |
| George Albert Wentworth - Algebra - 1894 - 204 pages
...+ bm + 6n + bp + cm -f- en + cp. To find the product of two polynomials, therefore, Multiply every **term of the multiplicand by each term of the multiplier, and add the partial products.** 88. In multiplying polynomials, it is a convenient arrangement to write the multiplier under the multiplicand,... | |
| William Frothingham Bradbury, Grenville C. Emery - Algebra - 1894 - 144 pages
...this equals Hence, for the multiplication of a polynomial by a polynomial, we have the following Bule. **Multiply each term of the multiplicand by each term of the multiplier, and** find the sum of the several products. 2. Multiply За2 — 2а6 + 462 by 2a — 3b. 3 a* — 2 а... | |
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