| Webster Wells - Algebra - 1885 - 324 pages
...d was аc — be — ad + &d. We have then the following rule for the product of two polynomials : **Multiply each term of the multiplicand by each term of the multiplier, and add the partial products.** EXAMPLES. 1. Multiply За — 2& by 2 а — 5&. In accordance with the rule, we multiply За —... | |
| Webster Wells - 1885 - 368 pages
...d was ac — be — aci + 6d. We have then the following rule for the product of two polynomials : **Multiply each term of the multiplicand by each term of the multiplier, and add the partial products.** EXAMPLES. 1. Multiply Зa — 26 by 2a — 56. In accordance with the rule, we multiply Зa — 26... | |
| George Albert Wentworth - Algebra - 1886 - 284 pages
...-\-bп -|- сn -\- ар -\-bр + ср. That is, to find the product of two polynomials, 71. Multiply **the multiplicand by each term of the multiplier and add the partial products** ; or, multiply each term of one factor by each term of the other, and add the partial products. 72.... | |
| Edward Brooks - Algebra - 1888 - 190 pages
...Adding the partial 2a2 — ab products, we have 2a2+3a6- 262. Therefore, etc. +4a6-26' 2a2 + 3a6-26« **Rule. — Multiply each term of the multiplicand by...term of the multiplier, and add the partial products.** a — 6 a +6 a2-a6 +a6-62 a3 -62 (6.) an-6" a2-6' a8 -62 an+Ja"68-a26"+6"+3 7. Multiply 3a - 26 by... | |
| Algebra - 1888 - 492 pages
...last partial product. The sum of these partial products gives the product required. Rule. — Multiply **the multiplicand by each term of the multiplier and add the partial products.** 83. 1. 4s. 6. 7. 8. 9. 10. EXERCISES. Multiply : a + b by a + b. 3ж + 2y by 2ж + 3y. 3ab + № by... | |
| Edward Albert Bowser - Algebra - 1888 - 868 pages
...ad— bc+bd (Art. 33). . . (4) Hence, to multiply one polynomial by another, we have the following **RULE. Multiply each term of the multiplicand by each term of the multiplier;** if the terms multiplied together have the same sign, prefix the sign + to the product, if unlike, prefix... | |
| George Albert Wentworth - 1888 - 268 pages
...+ an + bn -\-en + ap + bp + cp. That is, to find the product of two polynomials, 71. Multiply ¿he **multiplicand by each term of the multiplier and add the partial products** ; or, multiply each term of one factor by each term of the other, and add the partial products. 72.... | |
| Horatio Nelson Robinson - 1888 - 372 pages
...I. Write the several terms of the multiplier under the corresponding terms of the multiplicand. II. **Multiply each term of the multiplicand by each term of the multiplier,** beginning with the lowest term in each, an I call the product of any two denominations the denomination... | |
| William Frothingham Bradbury, Grenville C. Emery - Algebra - 1889 - 428 pages
...by-\-bz. Hence, for the multiplication of a polynomial by a polynomial, we have the following Ru1e. • **Multiply each term of the multiplicand by each term of the multiplier, and** find the sum of the several products. 2. Multiply 2 x2 + 3 xy — if by 3 x — 2 y. 2x* + 3xy —... | |
| Webster Wells - Algebra - 1890 - 604 pages
...Polynomials by Polynomials. By Art. 60, (1), = ac + be + ad + bd, bj Art. 60, (5). We then have the following **rule : Multiply each term of the multiplicand by each...term of the multiplier, and add the partial products.** 1. Multiply 3a — 26 by 2a — 56. In accordance with the rule, we multiply 3a— 2b by 2 a, and then... | |
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