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Multiply each term of the multiplicand by each term of the multiplier, and add the partial products.
The Inductive Algebra: Embracing a Complete Course for Schools and Academies - Page 46
by William James Milne - 1881 - 347 pages
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## The Scholar's Algebra: An Introductory Work on Algebra

Lewis Hensley - Algebra - 1875 - 274 pages
...(2) -5X-6. (3) 2 X 80. The general rule for the multiplication of two expressions will now be : — Multiply each term of the multiplicand by each term of the multiplier in succession, determining the sign of every product by the Rule of Signs ; then collect the terms,...
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## The Complete Algebra: Embracing Simple and Quadratic Equations, Proportion ...

Edward Olney - Algebra - 1877 - 466 pages
...5xy by — x'y1 . 16. To multiply two factors together when one or both are polynomials. R ULE. — MULTIPLY EACH TERM OF THE MULTIPLICAND BY EACH TERM OF THE MULTIPLIER, AND ADD THE PRODUCTS. Ex. 1. Multiply 2a'x — 3by + 4 m by Za'b'm. OPERATION. — It is immaterial 2a2z — Sby...
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## New Elementary Algebra: In which the First Principles of Analysis are ...

Benjamin Greenleaf - Algebra - 1877 - 662 pages
...sum of these - partial products is3a'-|-Soi-|"2^! the required product. Hence the following К ULE. Multiply each term of the multiplicand by each term of the multiplier separately, and add the partial products. EXAMPLES. (2.) (3.) 4« 3a + + 3 b 1, 5x X + 3у - 2у •...
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## The Complete Algebra: Embracing Simple and Quadratic Equations, Proportion ...

Edward Olney - Algebra - 1878 - 516 pages
...Sc'd1 by- ab; - 5xy by - x'y\ 10. To multiply tivo factors together whtn one or both are polynomials. RULE. — MULTIPLY EACH TERM OF THE MULTIPLICAND BY EACH TERM OF THE MULTIPLIER, AND ADD THE PRODUCTS. Ex. 1. Multiply 2a'x — Sby+lmby Za'Fm. OPERATION. — It is immaterial 2a2^ — Sby + 4m...
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## A University Algebra

Edward Olney - 1878 - 360 pages
...completed. 84. Prob. — To multiply two factors together when one or both are polynomials. R ULE. — MULTIPLY EACH TERM OF THE MULTIPLICAND BY EACH TERM OF THE MULTIPLIER, AND ADD THE PRODUCTS. DEM. — Thus, if any quantity is to be multiplied by a + b — c, if wo take it a tunes...
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## New Practical Algebra: Adapted to the Improved Methods of Instruction in ...

James Bates Thomson - Algebra - 1878 - 322 pages
...required. 98. The various principles developed in the preceding cases, may be summed up in one GENERAL RULE. Multiply each term of the multiplicand by each term of the multiplier, giving each product its proper sign, and each letter its proper exponent. The sum of the partial products...
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## New Elementary Algebra: Containing the Rudiments of the Science for Schools ...

Horatio Nelson Robinson - Algebra - 1879 - 332 pages
...adding the partial products. Hence Entire Product, 2a2 + 5a5 + 36s the RULE. — Multiply all the terms of the multiplicand by each term of the multiplier, and add the partial products. ENTIRE QUANTITIES. EXAMPLES FOR PRACTICE. Multiply By Product, Multiply By Product, Multiply By Product,...
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## New Elementary Algebra: Designed for the Use of High Schools and Academies

Benjamin Greenleaf - Algebra - 1879 - 322 pages
...sum of these partial products is 3 a" -f- 5 ab -f- 2 /r ; the required product. Hence the following RULE. Multiply each term of the multiplicand by each term of the multiplier separately, and add lhe partial products. EXAMPLES. (2.) (3.) 3 a -f- bx — ,2y 12 a2 -f- 9 ab 5 x2...
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## University Algebra

Webster Wells - Algebra - 1879 - 468 pages
...to the first. On this we base the following rule for finding the product of two polynomials. BULE. Multiply each term of the multiplicand by each term of the multiplier, remembering that like signs produce +, and unlike signs produce — , and add the partial products....
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## The junior student's algebra. [With] Answers to the examples

Alexander Wilson (M.A.) - 1879 - 228 pages
...multiplier and multiplicand are both compound expressions, the product will be found by multiplying each term of the multiplicand by each term of the multiplier, and combining the terms of these partial products. Ex. (i.) Multiply a2 - 3a + 2 by 2a - 4. a2- 3a + 2...
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