| Isaac Todhunter - Algebra - 1858 - 530 pages
...considering the above cases we arrive at the following rule for multiplying two binomial expressions. **Multiply each term of the multiplicand by each term of the multiplier;** if the terms have the same sign, prefix the sign + to the product, if they have different signs prefix... | |
| William Smyth - Algebra - 1858 - 344 pages
...From what has been done we have the following rule for the multiplication of polynomials, viz. 1°. **Multiply each term of the multiplicand by each term of the multiplier,** observing with respect to the signs, that if two terms multiplied together have each the same sign,... | |
| John Fair Stoddard, William Downs Henkle - Algebra - 1859 - 538 pages
...— Yaarjyd — Haxy~*c. CASE III. (91.) When both the multiplicand and multiplier are polynomials. **RULE. Multiply each term of the multiplicand by each term of the multiplier, and add the** products. PROBLEM. Multiply a' + 06 + 6* by a + 6. SOLUTION. Operation. a*+ a6 + 6' Multiplying a'... | |
| Horatio Nelson Robinson - Arithmetic - 1859 - 362 pages
...I. Write the several terms of the multiplier tinder the corresponding terms of the multiplicand. II. **Multiply each term of the multiplicand by each term of the multiplier,** beginning with the lowest term in each, and call the product of any two denominations the denomination... | |
| James B. Dodd - Arithmetic - 1859 - 368 pages
...RULE XXXI. (132.) To Multiply one Duodecimal Polynomial by another. 1. Proceeding from right to left, **multiply each term of the multiplicand by each term of the multiplier;** mark each product term with the proper index (131), and set similar terms one under another. 2. When... | |
| James Bates Thomson - Arithmetic - 1860 - 440 pages
...1. Place the several terms of the multiplier under the corresponding terms of the multiplicand. II. **Multiply each term of the multiplicand by each term of the multiplier** separately, beginning with the lowest denomination in the multiplicand, and the highest in the multiplier,... | |
| Philip Kelland - 1860 - 308 pages
...Propositions of the Second Book. 9. (a' - 62) x 5 (a2 + b') = 5 (a4 - 64) = 5al - 5b\ 10. (a- b + c) (a + be). **Multiply each term of the multiplicand by each term of the multiplier,** arranging the results as below : a — b + c a + b — c a' — ab + ac + ab - 62 + be — ac + be... | |
| Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...ay-\-az-\-bx — by-{-bz — ccr-f-cy— ex Hence the following general RULE. Multiply all the terms **of the multiplicand by each term of the multiplier, and add the partial products.** EXAMPLES FOK PRACTICE. (1.) (2.) (3.) 3o — 2bc bx'y+Zxy' 4a*m — Bed* — 3ac* 6a'— 4a'6c (4.)... | |
| Benjamin Greenleaf - 1863 - 338 pages
...sum of these 1 ' partial products is 3o? -\- 5ab -\- 2W; the required product. Hence the following **RULE. Multiply each term of the multiplicand by each term of the multiplier** separately, and add the partial products. EXAMPLES. (2.) (3.) 4a-f-3ft 5 ж 4- 3У 3а -\- bx — 2y... | |
| Benjamin Greenleaf - Algebra - 1864 - 420 pages
...and the sum of these partial products is 2ar" -|- xy — y*, the product required. Hence, the BULB. **Multiply each term of the, multiplicand by each term of the multiplier, and add the partial products.** EXAMPLES. (2.) (3.) (4.) 3a-)-5a; 8a2ic — d abc -\- m" 4m bad'2 4 am 12 am ' -\- 20 mx 40 a3 6 erf2... | |
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