 ... proportionally : and if the sides, or the sides produced, be cut proportionally, the straight line which joins the points of section, shall be parallel to the remaining side of the triangle.  A Treatise on Practical Gauging - Page 64by Anthony Nesbit, W. Little - 1822Full view - About this book
 | Robert Simson - Trigonometry - 1835 - 544 pages
...straight line which joins the points of section will be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of...the triangle ABC ; then BD is to DA, as CE to EA. Join BE, CD ; then the triangle BDE is equal to the triangle CDE % because they are on the same base... | |
 | John Playfair - Geometry - 1836 - 148 pages
...straight line which joins the points of section shall be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC ; BD is to DA, as CE to EA. Join BE, CD ; then the triangle BDE is equal to the triangle CDE (Cor.... | |
 | Andrew Bell - Euclid's Elements - 1837 - 290 pages
...straight line which joins the points of section shall he parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABO ; BD is to DA, as CE to EA. Join BE, CD ; then the triangle BDE is equal to the triangle CDE (I.... | |
 | Euclides - 1838 - 264 pages
...line which joins the points of section shall be parallel to the remaining side of the triangle, LetDE be drawn parallel to BC, one of the sides of the triangle ABC : BD shall be to DA, as CE to EA. «3, 1 Join BE, CD ; then the triangle BDE is equal' to the triangle... | |
 | Euclides - Geometry - 1841 - 378 pages
...straight line which joins the points of section shall be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC: then BD shall be to DA, as CE to EA. Join BE, CD; then the triangle BDE is equal* to the triangle CDE, because... | |
 | John Playfair - Euclid's Elements - 1842 - 332 pages
...straight line which , joins the points of section will be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC : BD is to DA as CE to EA. Join BE, CD ; then the triangle BDE is equal to the triangle CDE (37. 1.),... | |
 | Euclides - 1845 - 546 pages
...straight line nhich joins the points of section shall be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC. Then BD shall be to DA, as CE to EA. Join BE, CD. Then the triangle BDE is equal to the triangle CDE, (i. 37.)... | |
 | Euclid - Geometry - 1845 - 218 pages
...straight line which joins the points of section, shall be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC : BD is to DA, as CE to EA. Join BE, CD ; Then the triangle BDE is equal to the triangle CDE*, * «.i.... | |
 | Euclid, John Playfair - Euclid's Elements - 1846 - 334 pages
...straight line which joins the points of section will be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC : BD is to DA as CE to EA. Join BE, CD ; then the triangle BDE is equal to the triangle CDE (37. 1.),... | |
 | Anthony Nesbit - Plane trigonometry - 1847 - 492 pages
...then the angle ABC in that semi-circle, is a right angle. (Euc. III. 31. Simp. in. 13. Em. VI. 14.) THEOREM X. Let DE be drawn parallel to BC, one of...sides of the triangle ABC; then BD is to DA, as CE to E A. (Euc. VI. 2. Simp. IV. 12. Em. II. 12.) THEOREM XI. DB In the preceding figure, DE being parallel... | |
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