| Francis Henney Smith - Arithmetic - 1845 - 300 pages
...the first term, and the less in i/ie second. Multiply the second and third terms together, and divide by the first ; the quotient will be the fourth term or answer taught. PROOF. Multiply the extremes together, and also the means ; if the answer be correct, the two... | |
| Francis Henney Smith - Arithmetic - 1845 - 710 pages
...the first term, and the less in the second. Multiply the second and third terms together, and divide by the first ; the quotient will be the fourth term or answer sought. PROOF. Multiply the extremes together, and also the means ; if the answer be correct, the two... | |
| William Vogdes - Arithmetic - 1847 - 324 pages
...the first and second terms to the same denomination, and the third to the lowest name mentioned. 2. Multiply the second and third terms together, and...the product by the first; the quotient will be the answer to the question in the same denomination as the third term. 3. If either of the terms consists... | |
| rev. Frederick Calder - 1848 - 190 pages
...and if the third term consist of several denominations, reduce it to the lowest name mentioned. Then multiply the second and third terms together, and...the product by the first: the quotient will be the answer or fourth term, expressed in the same denomination as that in which the third term was left.... | |
| William B. Young - Ready-reckoners - 1848 - 320 pages
...second Terms to the same Jenomination, and to the lowest denomination mentioned in either of them@ ihen multiply the second and third Terms together, and divide the product by the first Term, the result will be the fourth Term or answer, in the same de nomination to which the third Term... | |
| Isaiah Steen - 1848 - 316 pages
...that place. Then, the first two terms being reduced to the same simple denomination, when necessary, multiply the second and third terms together, and divide the product by the first term; the quotient is the answer, or fourth proportional required; and it is always of the same denomination... | |
| Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 260 pages
...the least of the two remaining numbers fqr the second term, and the greater for the first term ; then multiply' the second and third terms together, and divide the -product by the first term, and the quotient will be the answer in the same name "of the third term EXAMPLES. 1. If 6 yards... | |
| J. M. Scribner - Mechanical engineering - 1849 - 286 pages
...of the two remaining numbers for the second term, and the greater for the first ; and in either case multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination as the third term. NOTE. — If the first... | |
| Rufus Putnam - Arithmetic - 1849 - 276 pages
...for the second term, and the other for the first. Divide the product of the second and third terms by the first; the quotient will be the fourth term or answer. The first and second terms must be of the same denomination ; the fourth will be of the same denomination... | |
| George Roberts Perkins - Arithmetic - 1850 - 364 pages
...written the three terms of the proportion, or, as usually expressed, having stated the question, then multiply the second and third terms together, and divide the product by the first term. NOTE. — Since there is a ratio between the firsthand second terms, they must be reduced to... | |
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