| Daniel Adams - Arithmetic - 1830 - 294 pages
...difference. Hence, when the extremes and number of terms are ffiven, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference. 6. If the extremes be 5 and 605, and the number... | |
| Ira Wanzer - Arithmetic - 1831 - 408 pages
...answer. PROBLEM III. — The extremes and the number of terms being given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1, and the quotient will be the common difference. EXAMPLE 1. If the extremes be 4 and 18, and the... | |
| Daniel Adams - Arithmetic - 1831 - 276 pages
...difference. Hence, when the extremes and number of terms are given, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference. 6. If the extremes be 5 and 605, and the number... | |
| Daniel Adams - Arithmetic - 1831 - 276 pages
...difference. Hence, when the extremes and number of terms are given, to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference. 6. If the extremes be 5 and 605, and the number... | |
| William Ruger - Arithmetic - 1832 - 282 pages
...striking. CASE III. — The extremes and number of terms being .given, to find the common difference. RULE — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference. EXAMPLES. 1. A merchant sold 200 yards of cloth... | |
| Zadock Thompson - Arithmetic - 1832 - 186 pages
...Hence, II. The first term, the last term, and the number of term* given to fmd the common difference. RULE. — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference. 2. If the first term of a series be 8, the last... | |
| Francis Walkingame - 1833 - 204 pages
...basket ? Ans. 5 miles, 1 300 yards. Case 2. The same three terms giren, tojind the common difference. RULE. Divide the difference of the extremes by the number of terms less 1 ; and the quotient will be the answer. (4) A man had eight sons, whose ages were in arithmetical... | |
| Catharine Esther Beecher - Arithmetic - 1833 - 296 pages
...difference. Hence, when the extremes and number of terms are given, to find the common difference, Divide the difference of the extremes, by the number of terms less 1. 2. Extremes 3 and 19 ; number of terms 9. Required the common difference. A. 2. 3. Extremes 4 and... | |
| Daniel Adams - Arithmetic - 1833 - 268 pages
...difference. ' Hence, when the extremes and number of terms are given, • to find the common difference, — Divide the difference of the extremes by the number of terms, less 1, and the quotient will be the common difference. 6. If the extremes be 5 and 605, and the number... | |
| George Alfred - Arithmetic - 1834 - 336 pages
...the two extremes and the number of terms are given, to find the common difference of all the terms. RULE. Divide the difference of the extremes by the number of terms less 1, and the quotient will be the common difference of all the terms. / , m . EXAMPLES. ' .:•• "... | |
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