 | Charles Westinghouse - Machine design - 1906 - 168 pages
...by the perpendicular height. Parallelogram : Area=D x H To find the area of a trapezoid— Fig. 92. Multiply half the sum of the two parallel sides by the perpendicular distance between the sides. Polygon: Area= No. of si Trapezoid: Area= (HE+D) To find the area of an equilateral triangle... | |
 | Alice Ravenhill - Hygiene - 1907 - 762 pages
...of a triangle. Base x perpendicular height, divide by 2. To find the area of a trapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, divide by 2. To find the area of any rectilinear figure. Divide the figure into triangles by lines... | |
 | Thomas Aloysius O'Donahue - Mine surveying - 1911 - 288 pages
...the area. Let S = |(AB + BC + CA). (12) (Fig. 63) Area = VS(S - AB)(S - BC)(S - OA). Trapezoid. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. B (13) (Fig. 64) Area = |(AD + BC) x DE. FIG. ' B Fio. 64. If the... | |
 | Charles Lingle Woodfield - Arithmetic - 1917 - 154 pages
...Surfaces I. To find the area of a square or a rectangle: Rule.— Multiply the length by the width. IL To find the area of a trapezoid: Rule. — Multiply half the sum of the parallel sides by the altitude. III. To find the area of a triangle: Rule. — Multiply the base by... | |
 | Frederick Thomas Hodgson - 1917 - 696 pages
...perpendiculars, de and bf, 18 and l(i feet? Problem IV. — To find the area of a trapezoid. Rule. — Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Example i. — Required the area of the trapezoid, abed, having... | |
 | Joseph Gregory Horner - 1920 - 416 pages
...is a rectilineal figure which has two sides only parallel. Its area is obtained thus : — Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Polygons. — Lastly, the area of any rectilineal polygonal... | |
 | Frank Eugene Kidder - Architecture - 1921 - 1950 pages
...the product by 2. Thus, ab X (ce + di) To find the area of a trape zoíd (Fig. j8). Rule. Multiply the sum of the two parallel sides by the perpendicular distance between them and divide the product by 2. To compute the area of an irregular polygon. Part 1 To find the are«... | |
 | R. H. Warn, John G. Horner - Crafts & Hobbies - 2002 - 292 pages
...trapezoid, which has only two of its sides parallel, is obtained by the rule — Rule 5. — Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. A quadrilateral is a rectilineal figure with four sides. But... | |
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To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area. 
