| Charles Westinghouse - Machine design - 1906 - 168 pages
...by the perpendicular height. Parallelogram : Area=D x H To find the area of a trapezoid— Fig. 92. **Multiply half the sum of the two parallel sides by the perpendicular distance between** the sides. Polygon: Area= No. of si Trapezoid: Area= (HE+D) To find the area of an equilateral triangle... | |
| Alice Ravenhill - Hygiene - 1907 - 762 pages
...of a triangle. Base x perpendicular height, divide by 2. To find the area of a trapezoid. Multiply **the sum of the two parallel sides by the perpendicular distance between them,** divide by 2. To find the area of any rectilinear figure. Divide the figure into triangles by lines... | |
| Thomas Aloysius O'Donahue - Mine surveying - 1911 - 288 pages
...the area. Let S = |(AB + BC + CA). (12) (Fig. 63) Area = VS(S - AB)(S - BC)(S - OA). Trapezoid. — **Multiply half the sum of the two parallel sides by the perpendicular distance between them,** and the product will be the area. B (13) (Fig. 64) Area = |(AD + BC) x DE. FIG. ' B Fio. 64. If the... | |
| Charles Lingle Woodfield - Arithmetic - 1917 - 154 pages
...Surfaces I. To find the area of a square or a rectangle: Rule.— Multiply the length by the width. IL **To find the area of a trapezoid: Rule. — Multiply half the sum of the** parallel sides by the altitude. III. To find the area of a triangle: Rule. — Multiply the base by... | |
| Frederick Thomas Hodgson - 1917 - 716 pages
...perpendiculars, de and bf, 18 and l(i feet? Problem IV. — To find the area of a trapezoid. Rule. — Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. Example i. — Required the area of the trapezoid, abed, having... | |
| Joseph Gregory Horner - 1920 - 418 pages
...is a rectilineal figure which has two sides only parallel. Its area is obtained thus : — Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. Polygons. — Lastly, the area of any rectilineal polygonal... | |
| Frank Eugene Kidder - Architecture - 1921 - 1944 pages
...the product by 2. Thus, ab X (ce + di) To find the area of a trape zoíd (Fig. j8). Rule. Multiply **the sum of the two parallel sides by the perpendicular distance between them** and divide the product by 2. To compute the area of an irregular polygon. Part 1 To find the are«... | |
| R. H. Warn, John G. Horner - Technology & Engineering - 2002 - 292 pages
...trapezoid, which has only two of its sides parallel, is obtained by the rule — Rule 5. — Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. A quadrilateral is a rectilineal figure with four sides. But... | |
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