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To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area.
A System of Geometry and Trigonometry: Together with a Treatise on Surveying ... - Page 33
by Abel Flint - 1804 - 168 pages

## New Practical Arithmetic

Eugene L. Dubbs - Arithmetic - 1901 - 462 pages
...around B's farm cost \$180, what should have been the cost of that around A's, at the same rate ? 225. To find the area of a trapezoid. RULE. Multiply half the sum of the parallel sides by the altitude. 1. A floor is 25 ft. long, and its two ends are respectively 16 ft....

## The Mechanical Engineer's Pocket-book: A Reference Book of Rules, Tables ...

William Kent - Engineering - 1907 - 1206 pages
...the sum of tile perpendiculars let fall on it from opposite angles. Area of a trapezold = product of half the sum of the two parallel sides by the perpendicular distance between them. To find the area of any quadrilateral figure.— Divide the quadrilateral into two triangles; the sum...

## The Mechanical Engineer's Pocket-book: A Reference Book of Rules, Tables ...

William Kent - Engineering - 1902 - 1206 pages
...sum of the perpendiculars let fall on it from opposite angles. Area of a trapezold = product of naif the sum of the two parallel sides by the perpendicular distance between them. To find the area of any quadrilateral figure.— Divide the quadrilateral into two triangles; the sum...

## The Advanced Machinist: A Practical and Educational Treatise, with Illustrations

Nehemiah Hawkins - Machine-shop practice - 1903 - 362 pages
...Fig- 7TO FIND THE AREA OF A TRAPEZOID. A Trapezoid is a trapezium having two of its sides parallel. RULE. — Multiply half the sum of the two parallel...sides by the perpendicular distance between them. 62 USEFUL MEASUREMENTS. Let the figure be the trapezoid, the sides 7 and 5 being parallel ; and 3 the...

## Ray's Modern Practical Arithmetic: A Revised Edition of Ray's Practical ...

Joseph Ray - Arithmetic - 1903 - 364 pages
...25£ yd. 13. A rectangular field is 15 rd. long. What must be its width to contain 1 A. ? 10J rd. 248. To find the area of a trapezoid: Rule. — Multiply half the sum of the parallel sides by the altitude. EXPLANATION. — The base of a parallelogram having the same altitude...

## Hodgson's Estimator and Contractor's Guide for Pricing Builder's Work ...

Frederick Thomas Hodgson - Architecture, Domestic - 1904 - 364 pages
...feet? HX 8=336 i =714 sq.ft. Ans. Problem IV. — To find the area of a trapezoid. Rule. — Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Example i. — Required the area of the trapezoid, abed, having...

## Henley's Encyclopaedia of Practical Engineering and Allied Trades ...

1906 - 582 pages
...area may be found by the above rule for trapeziums, but generally it is calculated by the following rule: — Multiply half the sum of the two parallel...sides by the perpendicular distance between them. AREA OF THE CIRCLE. — The area of the circle may be found by any of the following three methods :...

## Henley's Encyclopędia of Practical Engineering and Allied Trades: A ...

Joseph Gregory Horner - Engineering - 1906 - 572 pages
...area may be found by the above rule for trapeziums, but generally it is calculated by the following rule: — Multiply half the sum of the two parallel...sides by the perpendicular distance between them. AREA OF THE CIRCLE. — The area of the circle may be found by any of the following three methods :...