| Eugene L. Dubbs - Arithmetic - 1901 - 462 pages
...around B's farm cost $180, what should have been the cost of that around A's, at the same rate ? 225. **To find the area of a trapezoid. RULE. Multiply half the sum of the** parallel sides by the altitude. 1. A floor is 25 ft. long, and its two ends are respectively 16 ft.... | |
| William Kent - Engineering - 1907 - 1206 pages
...the sum of tile perpendiculars let fall on it from opposite angles. Area of a trapezold = product of **half the sum of the two parallel sides by the perpendicular distance between them.** To find the area of any quadrilateral figure.— Divide the quadrilateral into two triangles; the sum... | |
| William Kent - Engineering - 1902 - 1206 pages
...sum of the perpendiculars let fall on it from opposite angles. Area of a trapezold = product of naif **the sum of the two parallel sides by the perpendicular distance between them.** To find the area of any quadrilateral figure.— Divide the quadrilateral into two triangles; the sum... | |
| Nehemiah Hawkins - Machine-shop practice - 1903 - 362 pages
...Fig- 7TO FIND THE AREA OF A TRAPEZOID. A Trapezoid is a trapezium having two of its sides parallel. **RULE. — Multiply half the sum of the two parallel...sides by the perpendicular distance between them.** 62 USEFUL MEASUREMENTS. Let the figure be the trapezoid, the sides 7 and 5 being parallel ; and 3 the... | |
| Joseph Ray - Arithmetic - 1903 - 364 pages
...25£ yd. 13. A rectangular field is 15 rd. long. What must be its width to contain 1 A. ? 10J rd. 248. **To find the area of a trapezoid: Rule. — Multiply half the sum of the** parallel sides by the altitude. EXPLANATION. — The base of a parallelogram having the same altitude... | |
| Frederick Thomas Hodgson - Architecture, Domestic - 1904 - 364 pages
...feet? HX 8=336 i =714 sq.ft. Ans. Problem IV. — To find the area of a trapezoid. Rule. — Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. Example i. — Required the area of the trapezoid, abed, having... | |
| 1906 - 582 pages
...area may be found by the above rule for trapeziums, but generally it is calculated by the following **rule: — Multiply half the sum of the two parallel...sides by the perpendicular distance between them.** AREA OF THE CIRCLE. — The area of the circle may be found by any of the following three methods :... | |
| Joseph Gregory Horner - Engineering - 1906 - 572 pages
...area may be found by the above rule for trapeziums, but generally it is calculated by the following **rule: — Multiply half the sum of the two parallel...sides by the perpendicular distance between them.** AREA OF THE CIRCLE. — The area of the circle may be found by any of the following three methods :... | |
| Calvin Franklin Swingle, Frederick John Prior - Air-brakes - 1906 - 676 pages
...by the perpendicular height. Parallelogram : Area = DXH To find the area of a trapezoid— Fig. 45. **Multiply half the sum of the two parallel sides by the perpendicular distance between** the sides. ' (HE+D) Trapezoid: Area—- UD ») Fig. 46. To find the area of an equilateral triangle—... | |
| Joseph H. Rose - Sheet-metal work - 1906 - 340 pages
...by the perpendicular height. Parallelogram : Area = DXH To find the area of a trapezoid— Fig. 59. **Multiply half the sum of the two parallel sides by the perpendicular distance between** the sides. _ . , . (HE + D) TrapezoId : Area = ^ To find the area of an equilateral triangle — Fig.... | |
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