| William Paterson (Lieut.-Col.) - Military topography - 1882 - 204 pages
...perpendicular, and half the product will be the area. ~. = Triangla To find the area of a trapezoid : — **Multiply half the sum of the two parallel sides by the perpendicular distance between them** for the area. — - — a = Trapezoid. To find the area of a trapezium : — Multiply the diagonal... | |
| Joseph Bateman - Auctions - 1882 - 576 pages
...convenient number of feet and inches. For a Trapezoid (two of the sides parallel, but not equal).—Multiply **half the sum of the two parallel sides by the perpendicular distance between them.** For a Trape.zinm (four straight sides of different lengths).—Obtain a diagonal, by measuring from... | |
| William Dodds - 1883 - 202 pages
...area of a trapezoid when the parallel sides and the perpendicular distance between them are given. **RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them,** and the product will be the area. If two straight "iT lines are of unequal ! / length, the average... | |
| William John Macquorn Rankine - 1883 - 452 pages
...by a pair of' parallel straight lines, and a pair of straight lines not parallel). Multiply the half **sum of the two parallel sides by the perpendicular distance between them.** 3. Triangle. RULE A. — Multiply the length of any one of the sides by one-half of its perpendicular... | |
| William Waterston - 1884 - 298 pages
...the square of 3 being 9, we have 9 X 3.1416 - 28-2744 square miles. 10. Area of a trapezoid: Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and take half the product. Ex. The parallel sides are 4.32 feet and 5.48 feet, and the perpendicular... | |
| Education - 1885 - 630 pages
...Mensuration. Answer one Question. I. State and prove the rule for finding the area of a trapezoid. **Multiply half the sum of the two parallel sides by the perpendicular distance between them,** and the product will give the area. sides. The area of ABCDs=$ AB and CD x perpendicular distance BG... | |
| M. P. Caldwell - Arithmetic - 1883 - 198 pages
...garden whose area is J an acre; it is 110 yards long; how wide is it? Ans. 22 yds. PROPOSITION 5.— **To find the area of a trapezoid. RULE. — Multiply half the sum of the** parallel sides by the altitude, and the product is the area. Or, place the altitude and half the sum... | |
| Frank Eugene Kidder - Architecture - 1886 - 640 pages
...(ce + i 2 FJ. '9-27 = area (Fig. 27). To Jind the area of a trrtpezoicl (Fig. 28). HULK. — Multiply **the sum of the two parallel sides by the perpendicular distance between them,** anil divide the product by 2. To compute the area of an irregular polygon. RULE. — Divide the polygon... | |
| John H. Macke - Carpet laying - 1891 - 244 pages
...than a right angle? If less or greater than a right angle, what is the proper definition of the angle? **To find the area of a trapezoid. RULE. Multiply HALF THE SUM of the two parallel sides by the** altitude of the trapezoid; that is, by the distance between the two parallel sides. Example. Find the... | |
| Frank Eugene Kidder - Architecture - 1892 - 1032 pages
...X (ce + di) F'3.27 = area (Fig. 27). To find, the area of a trapczoid (Fig. 28). RULE. — Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and divide the product by 2. To compute the area of an irregular polygon. RULE. — Divide the polygon... | |
| |