| Elias Loomis - Logarithms - 1859 - 372 pages
...one of its sides multiplied by the square root of 3. MENSURATION OF SURFACES. 63 PROBLEM III. (87.) **To find the area of a trapezoid. RULE. Multiply half the sum of the** parallel sides into their per . pendicular distance. For demonstration, see Geometry, Prop. 7, B. IV.... | |
| Josiah Lyman - Electronic book - 1862 - 92 pages
...the field. SECOND METHOD. (S9.) BY TRAPEZOIDS AND TRIANGLES. For a Trapezoid, the rule is, Multiply **the sum of the two parallel sides by the perpendicular distance between them.** Half the product will be the area. For a Triangle, Multiply the base by the perpendicular height, and... | |
| Charles Davies - Arithmetic - 1863 - 346 pages
...ABCD, having two of its sides, AB, DC, parallel. The perpendicular, CE, is called, the altitude. 393. **To find the area of a trapezoid. Rule. — Multiply half the sum of the two parallel** lines by the altitude, and the product will be the area. (Bk. IV., Prop. VII.) Examples. 1. Required... | |
| Emerson Elbridge White, Henry Beadman Bryant - Bookkeeping - 1865 - 344 pages
...QUADRILATERALS, PENTAGONS, &c. ART. 176- (1.) To find the area of any quadrilateral having two sides parallel. **RULE. — Multiply half the sum of the two parallel sides by the** altitude, or perpendicular distance between those sides, and the product will be the area. NOTE. —... | |
| William John Macquorn Rankine - Engineering - 1866 - 356 pages
...by a pair of parallel straight lines, and a pair of straight lines not parallel). Multiply the half **sum of the two parallel sides by the perpendicular distance between them.** 3. Triangle. RULE A. — Multiply the length of any one of the sides by one-half of its perpendicular... | |
| Edward Thomas Stevens - 1866 - 434 pages
...which has only two of its opposite sides parallel, as ABD c. AE is the perpendicular. c K u To Jind **the area of a trapezoid. RULE : — Multiply half the sum of the** parallel sides by tho perpendicular distance between them ; the product is the area. DD THE CIRCLE.... | |
| Gerardus Beekman Docharty - Geometry - 1867 - 474 pages
...and 25.69 chains respectively, to find the area. Ans. 61 acres, 2 roods nearly. PROBLEM VI. Tojind **the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the** altitude of the trapezoid. (Geom., BI, th. 29.) Or, Multiply the altitude by the distance between the... | |
| Isaac Todhunter - Measurement - 1869 - 312 pages
...Thus we obtain the rule which will now be given. 161. To find the area of a trapezoid. RULE. Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. 162. Examples : (1) The two parallel sides of a trapezoid are... | |
| Emerson Elbridge White - Arithmetic - 1870 - 350 pages
...altitude. 4. To find the area of any quadrilateral having two sides parallel, Multiply one half of **the sum of the two parallel sides by the perpendicular distance between** tiiem. 5. To find the circumference of a circle, 1. Multiply the diameter by 3.1416. Or, 2. Divide... | |
| J Alfred Skertchly - 1873 - 184 pages
...two of its sides parallel, such as OPWC, is called a trapezoid; and its area is found by multiplying **half the sum of the two parallel sides by the perpendicular distance between them.** Here the area of 0 PWC equals | (O P+CW) x O C. The ordinate OP denotes the initial velocity, and C... | |
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