| William Chambers, Robert Chambers - Encyclopedias and dictionaries - 1842
...area comprised within the quadrilateral. The area of a trapezoid is generally found by multiplying **half the sum of the two parallel sides by the perpendicular distance between them** ; the area of a trapezium may likewise be found in the same way. When it ia desired to ascertain the... | |
| J. M. Scribner - Measurement - 1844 - 123 pages
...chains 1 Am. 3207 A. 2 R. PROBLEM IV. To find the area of a Trapezoid. ' ART. 12. Rule. — Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. Ex. 1. Required the area of the trape- D c zoid ABCD, having... | |
| P. O'Shaughnessy (Civil engineer) - Civil engineering - 1848 - 110 pages
...of a triangle, having the base 82 chains and the altitude 20. 12 chains. Ans. 82a lr 3|P. Prob. 3. **To find the area of a trapezoid. Rule — Multiply half the sum of the two** perpendiculars by the base, and the product will be area. (The truth of this rule is manifest, as the... | |
| Thomas Tate (mathematical master.) - 1848 - 284 pages
...required the area. Ans. 6 ac. 2 r. 12-5 p. S. PROBLEM. To find the area of a trapezoid. RULE. Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. (See Geo. Art. 43.) Note. The area of any irregular figure may... | |
| Benjamin Greenleaf - Arithmetic - 1849 - 336 pages
...318. ATRAPEZOID is a quadrilateral, which has only one pair of its opposite sides parallel. ART. 319. **To find the area of a trapezoid. RULE. — Multiply half the sum of the** parallel sides by the altitude, and the product is the area. 1. What is the area of a trapezoid, the... | |
| Almon Ticknor - Measurement - 1849 - 144 pages
...and 40-5 perches? PROBLEM 24.— THE TEAPEZOID. To find the area of a trapezoid. RULE. — Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. 1. Required the area of the trapezoid ABCD, whose parallel sides... | |
| J. M. Scribner - Mechanical engineering - 1849 - 264 pages
...16 feet? 42x9 = 378 ) _, 42X8=336 ( PROBLEM IV. To find the Area of a Trapecoid. Rule. — Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. Example 1. — Required the area of the trapezoid, abed, having... | |
| Charles Guilford Burnham - 1850 - 352 pages
...three sides of a triangle are 6, 8, and 10 chains. What is the area ? Ans. 24 chains. Art. 271, — **To find the area of a trapezoid. RULE. Multiply half...parallel sides by the perpendicular distance between them** : the product will be the area. 1. What is the area of a piece of land that is 30 chains long, 20 chains... | |
| George Roberts Perkins - Arithmetic - 1850 - 372 pages
...Hence the area of the trapezoid, which is the sum of the two-triangles, may be found by the following **RULE. Multiply half the sum of the two parallel sides by the** altitude. This rule has a fine application in measuring a tapering board, as A BCD. In this case half... | |
| Alexander INGRAM (of Leith.) - 1851 - 204 pages
...diagonal 127 poles. Ans. 3661-8734 per. = 22 ac. 3 ro. 21 per. 26 yds. 3'78 ft. QUADRILATERALS. PROB. VII. **To find the area of a trapezoid. RULE. Multiply half the sum of the** parallel sides by the perpendicular from the one to the other. That is, ^(AD + BC) X AE = the area.... | |
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