 | James Bates Thomson - Arithmetic - 1847 - 426 pages
...first. III. finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer together, and if the product is equal... | |
 | Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 260 pages
...tnc terms the same as in the Rule of Three Direct. 2. Multiply the first and second terms together, and di•vide the product by the third, the quotient will be the answer in the same . denomination that the middle term was reduced to. EXAMPLES. 1 . If 10 men can dig a ditch in 1'8 days, how many... | |
 | Nathan Daboll - Arithmetic - 1850 - 254 pages
...the Rule of Three Direct. 2. Multiply the first and second terms together, and divide the pro duct by the third; the quotient will be the answer in the same deno ruination as the middle term was reduced into. EXAMPLES. 2. If a man perform a journey in 5 days,... | |
 | Janet Taylor - Nautical astronomy - 1851 - 674 pages
...required. Multiply the second and third terms together, and divide the product by the first term, then the quotient will be the answer in the same denomination as the second term, observing to point off the decimal places according to the directions already given. Examples.... | |
 | Arithmetic - 1852 - 202 pages
...terms together, and divide the product by the first term ; the quotient will be the fourth term, or answer, in the same denomination as the second, or that to which the second was reduced. EXAMPLE If 2 yards of muslin cost 4 shillings, what will 6 yards cost ? yds. «. yds. 2 : 4 : : 6 4 2)24 12 Answer.... | |
 | William Tinwell - 1852 - 250 pages
...are marked with an asterisk, for the divisor, and the other three terms for a dividend ; divide, and the quotient will be the answer in the same denomination as the middle number. 1. If 100 men make three miles of road in 27 days, in how many days will 150 men make... | |
 | James Bates Thomson - Arithmetic - 1862 - 436 pages
...first. III. Finally, multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer together, and if the product is equal... | |
 | Francis Walkingame - 1868 - 154 pages
...denomination may be convenient. Multiply the second and third terms together, and divide by the first; the quotient will be the answer, in the same denomination as the third term. PROOF.—As the third term is to the answer, so is the first term to the second. EXAMPLES.... | |
 | Lorenzo Fairbanks - 1875 - 472 pages
...and the larger the first. III. Divide the product of the second and third terms by the first term ; the quotient will be the answer in the same denomination as the third term. NOTES.—1. To abridge the operation of multiplying and dividing, first cancel equal factors... | |
 | Thomas Liddell Ainsley - 1880 - 866 pages
...the first. Then multiply the second and third terms together, divide the product by the first, and the quotient will be the answer in the same denomination as the third term. The arrangement of the given terms in the manner mentioned at the beginning of the rule,... | |
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Direct. 2. Multiply the first and second terms together, and divide the product by the third ; the quotient will be the answer in the same denomination as the middle term was reduced into. 
