 | Frederick Emerson - Arithmetic - 1842 - 296 pages
...The common difference. The gum of all the terms. PROBLEM. I. The extremes and number of terms being given, to find the sum of all the terms. RULE. Multiply the sum of the extremes by the number of the terms, and half the product will be the sum of all the terms. See Theorem 4th. 1. The first term... | |
 | Osman Call - Arithmetic - 1842 - 200 pages
...common difference 1£, what is the number of terms? Ans. 4. THE FIRST AND LAST TERM, AND THE NUMBER OP TERMS GIVEN, 'TO FIND THE SUM OF ALL THE TERMS. RULE. — Multiply the sum of the first and last term by ike number of terms, and half the product will be the sum of all the terms.... | |
 | Benjamin Greenleaf - Arithmetic - 1843 - 340 pages
...years old, and the oldest S9. What is the common difference of their ages ? Ans. 2 years. PROBLEM II. The first term, the last term, and the number of terms...number of terms, and half the product will be the sum. 5. The extremes of an arithmetical series are 3 and 45, and the number of terms 22. Required the... | |
 | Nathan Daboll - Arithmetic - 1843 - 254 pages
...increase ? Ans. Daily increase 2 miles. CASE III. The first term, last term, and number of terms given, tq find the sum of all the terms. RULE. Multiply the...half the product will be the answer. EXAMPLES. 1. A man bought 12 yards of cloth in arithmetical progression. For the first yard he gave 6 cents, and... | |
 | Charles WATERHOUSE - Arithmetic - 1844 - 228 pages
...the difference of the extremes by the number of terms less 1, the quotient will be the difference. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of all the terms. Qtitf lions. — What is Arithmetical Progression? — When are numbers an ascending... | |
 | Benjamin Greenleaf - 1845 - 334 pages
...the last term, and the number of terms given to find the sum of all the terms. RULE. Multiply tint sum of the extremes by the number of terms, and half the product will be the sum. 5. The extremes of 'an arithmetical series are 3 and 45, and the number of terms 22. Required... | |
 | Arithmetic - 1845 - 196 pages
...difference, and to the product add the first term, the sum is the last term. 2. Multiply the sum of the two extremes by the number of terms, and half the product will be the sum of all the terms. EXAMPLES. 1 . The first term of a certain series in arithmetical progression... | |
 | Almon Ticknor - Arithmetic - 1846 - 276 pages
...term, the last term, and the number of terms, being given, to find the sum of all the terms. RULE II, Multiply the sum of the extremes by the number of terms, and half the product will be the answer. 3. A lady purchased 19 yards of riband, for which she gave Ic. for the first yard, 3c. for the second,... | |
 | James Bryce - 1846 - 352 pages
...bfk dhm ' hence, aei : bfk : : cgi : dhm. 177. PROB. I. To find the sum of an equidifferent series. Multiply the sum of the extremes by the number of terms, and take half the product. Let a be the first term, d the common difference, and s the sum of the series... | |
 | Frederick Emerson - Arithmetic - 1846 - 318 pages
...The common difference. The sum of all the terms. PROBLEM, i. The extremes and number of terms being given, to find the sum of all the terms. RULE. Multiply the $um of the extremes by the number of the terms, and half the product will 6e the sum of all the terms.... | |
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... the terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. 
