 | Frederick Emerson - Arithmetic - 1834 - 300 pages
...The common difference. The sum of all the terms. PROBLEM. I. The extremes and number of terms being given, to find the sum of all the terms. RULE. Multiply the sum of the extremes by the number of the terms, and half the product will be the sum of all the terms. See Theorem 4th. 1. The first term... | |
 | James L. Connolly (mathematician.) - Arithmetic - 1835 - 264 pages
...14; and 5+9=14. Progressions are best understood by Algebra. The first term, the last term, and ike number of terms, given to find the sum of all the terms. RULE. Multiply the sum of the two extremes by the number of terms, and half that product will be the answer; or multiply the sum... | |
 | Stephen Pike - Arithmetic - 1835 - 210 pages
...difference, and to the product add the first ,erm, the sum is fhe. last term. 2. Multiply the sum of the two extremes by the number of terms, and half the product will be the sum of all the terms. EXAHPLES. 1. The first term of a certain series in arithmetical progression is... | |
 | Luther Ainsworth - Arithmetic - 1837 - 306 pages
...series. Q. What is the RULE in this case ? A. Add the two extremes together, and multiply their sum by the number of terms, and half the product will be the answer, or sum of the series. 1. The first term of an arithmetical series is 3, the last term 63, and the number... | |
 | Luther Ainsworth - Arithmetic - 1837 - 298 pages
...series. Q. What is the RULE in this case ? A. Add the two extremes together, and multiply their sum by the number of terms, and half the product will be the an. swer, or sum of the scries. EXAMPLES. 1. The first term of an arithmetical series is 3, the last... | |
 | James Thomson (LL.D.) - Arithmetic - 1837 - 296 pages
...Answ. 243J. RULE II. The extremes and the number of terms being given, to find the sum of the series .- Multiply the sum of the extremes by the number of terms, and take half the product. Exam. 2. The first term of an equidifferent series is I , its last term 312,... | |
 | Nathan Daboll - 1839 - 220 pages
...increase Ans. Daily increase 2 mile: CASE III. Thf first term, last term, and number of terms gwent t find the sum of all the terms. • RULE. Multiply the sum of the extremes by the number of term: and half the product will be the answer. EXAMPLES, 1. A man bought 12 yards of cloth in arithmetical... | |
 | Benjamin Greenleaf - Arithmetic - 1839 - 356 pages
...The first term, the last term, and the number of terms given to find the sum of all the terms. EULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum. 5. The extremes of an arithmetical series are 3 and 45, and the number of terms 22. Required the... | |
 | Joseph Stockton - Arithmetic - 1839 - 218 pages
...and to the product add the first term, the sum will be the last term. 2. Multiply the sum of the two extremes by the number of terms, and half the product will be the sum of all the terms. EXAMPLE. 1. A merchant bought 50 yards of linen, at 2 cents for the first yard,... | |
 | Daniel Adams - 1839 - 268 pages
...) Hence, when the extremes and the number of terms are given, to find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
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... the terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. 
