 | Roswell Chamberlain Smith - Arithmetic - 1827 - 216 pages
...series increases or diminishes. PROBLEM I. — The first term, the last term, (ie the two extremes) and the number of terms given to find the sum of all...terms. RULE. — Multiply the sum of the extremes by half the num. Чег of terms, the product will be the answer. EXAMPLES. — How many times does a... | |
 | Daniel Adams - Arithmetic - 1848 - 322 pages
...extremes of the series ; hence, rvhen the extremes and the number of terms are given to find the sum of the terms, RULE. Multiply the sum of the extremes...number of terms, and half the product will be the sum of the terms. EXAMPLES FOR PRACTICE. 2. If the extremes be 5 and 605, and the number of terms 151,... | |
 | James Ryan - Arithmetic - 1827 - 290 pages
...PROBLEM If. — The extremes and the number of terms leing given, to find the sum of the series. 206. RULE. — Multiply the sum of the extremes by the number of terms, and take half the product. * Thereason of this operation will be manifest from the consideration, that... | |
 | Zachariah Jess - Arithmetic - 1827 - 226 pages
...add the first term, the sum is the last term. Secondly, Multiply the sum of the first and last term by the number of terms, and half the product will be the sum of the series. EXAMPLES. 1. Bought 19 yards of shalloon, at 1 cent for the first yard, 3 cents... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...found. PROBLEM I. The first term, the last term, and the number of terms being given, to find the stun of all the terms. RULE. Multiply the sum of the extremes...number of terms, and half the product will be the sum of the terms. Examples. 53+5=68 The sum of the extremes. Then 58x9+2=261 Ans, а. How many strokes... | |
 | Nathan Daboll - Arithmetic - 1828 - 262 pages
...best understood by an algebraic srowss, tn<? are, here ovrMteiL • - ' ARITHMETICAL PRdGRE88ION. % RULE. ; . Multiply the sum of the extremes by the...of terms, and half the product will be the answer. EXAMPLE8. N. 1. The first term of an arithmetical series is 3, the last term 23, and the number of... | |
 | Nathan Daboll - Arithmetic - 1828 - 268 pages
...Probkrns ; but must of them are best understood by an algebraic py^eest, Mu.' a.-e hare unritted. \ RULE. Multiply the sum of the extremes by the number of terms, and halt' the product will be the answer. EXAMPLE8. 1. The first term of an arithmetical series is 3, the... | |
 | Montgomery Robert Bartlett - Education - 1828 - 426 pages
...term, the sum will be the last term. 2. Add the first and the last terms together, and multiply the sum by the number of terms, and half the product will be the sum of all the terms. Thus:— • (1) What is the last term, and the number of terms of an arithmetical... | |
 | Daniel Adams - Arithmetic - 1828 - 286 pages
...Hence, when the. extremes and the number of terms are given, to find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will be the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
 | Daniel Adams - Arithmetic - 1828 - 266 pages
...Hence, when the extremes and the number of terms are given, '.o find the sum of all the terms, — Multiply £ the sum of the extremes by the number of terms, and the product will b« the answer. 10. If the extremes be 5 and 605, and the number of terms 151, what... | |
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... the terms, RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. 
