 | Nathan Daboll - Arithmetic - 1828 - 250 pages
...subtract it (always) from as many periods of the given number as you have found figures in the root. 7. Bring down the first figure of the next period to...remainder for a new dividend, to which find a new divisor Iia before, and in like manner proceed till the whole be finished. NOTE. — When the number to be... | |
 | Zadock Thompson - Arithmetic - 1828 - 238 pages
...root. Involve the whole root to the given power; suhtract it from the given nomher as hefore, hring down the first figure of the next period to the remainder for a new dividend, to which find a new divisor, and so on till the whole is finished. QUESTIONS FOR PRACTICE. 1. What is the cuhe root of 48228544... | |
 | Nathan Daboll - Arithmetic - 1828 - 262 pages
...(always) from as many periods ol the given num ber as you have found figures in the root. r. Bringdown the first figure of the next period to the remainder for a new dividend, to which find a new divi•or, as before, and in Kke manner proceed till the whole be finished. . NOTE. — When the number... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...quotient. 6. Involve the whole root to the given power, and subtract it uom the given number, as before. 7. Bring down the first figure of the next period to the remainder for a new resolver«! ; find a new divisor as before, ano proceed in like manner until the whole is finished.... | |
 | Nathan Daboll - Arithmetic - 1829 - 268 pages
...subtract it (a!.ways) from as many periods of the given number as you have found figures in the root. 7. Bring down the first figure of the next period to...for a new dividend, to which find a new divisor as br.-fore, and in like manner proceed till the whole be finNOTE. — When the number to be subtracted... | |
 | Arithmetic - 1831 - 198 pages
...divisor; by which find a seconu figure of the root. 4. Involve the whole ascertained root to the giver; power, and subtract it from the' first and second...and so proceed. Note. — The roots of the 4th, 6th, Sth, 9th, and 12th powers, may be obtained more readily thus: For the 4th root take the square, root... | |
 | William Ruger - Arithmetic - 1832 - 282 pages
...and multiply it by the number denoting the given power, for a divisor; by which find a second figure of the root. 4.. Involve the whole ascertained root...which, find a new divisor, as before, and so proceed, till the work is finished. NOTE— The roots of the 4th, 6th, 8th, 9th and 12th powers, may be obtained... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...the root. Involve the whole root to the given power ; subtract it from the given number as before, bring down the first figure of the next period to the remainder for a new dividend, to which find & new divisor, and so on till the whole is finished. QUESTIONS FOR PRACTICE. 1. What is the cube root... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...the root. Involve the whole root to the given power ; subtract it from the given number as before, bring down the first figure of the next period to the remainder for a. new dividend, to which find & new divisor, and so on till the whole is finished. QUESTIONS FOR PRACTICE. 1. What is the cube root... | |
 | Nicolas Pike - Arithmetic - 1832 - 540 pages
...given power, and subtract it from the gicen number, as before. 7. Bring down the first figure of tho next period to the remainder for a new dividend, to which find a new divisor, as belore and, in like manner, proceed till the whole be finished. EXAMPLES. 1st. What is the cube root... | |
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Bring down the first figure of the next period to the remainder for a new dividend, to which find a new divisor as before, and in like manner proceed till the whole be finished. 
