 RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity.  A Treatise on Practical Gauging - Page 182by Anthony Nesbit, W. Little - 1822Full view - About this book
 | Tobias Ostrander - Measurement - 1834 - 182 pages
...ends are right parallelograms. ~ ~ " PROBLEM XVIII. To find the solidity of a prismoid. Rule — To the sum of the areas of the two ends, add four times...parallel to, and equally distant from, both ends, arid this last sum multiplied by | of the height will give the solidity. EXAMPLES. 1. What is the solidity... | |
 | John Bonnycastle - Measurement - 1835 - 308 pages
...height to be 17.14508 inches? Ans. 3.1006/eef. PROBLEM XI. To find the solidity of a prismoid. RULE.* To the sum of the areas of the two ends add four times...section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity. Note.— The length of the... | |
 | Mathematics - 1836 - 488 pages
...hight of the wedge and the breadth of the base. To ßnd the solidity of a rectangular prismoid. To the areas of the two ends, add four times the area of a parallel section equally distant from the ends, and multiply the sum by ^ of the hight. A solid is... | |
 | Thomas Holliday - Surveying - 1838 - 404 pages
...and breadth of each end, and the perpendicular distance between them, for the solidity. Rule.—To the sum of the areas of the two ends, add four times...section parallel to and equally distant from both ends, and this last sum multiplied by one-sixth of the height, will give the solidity. Nule. The length of... | |
 | Jeremiah Day - Geometry - 1838 - 416 pages
...what is the solidity ? Ans. 5040, PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY £ OF THE HEIGHT, Let L and... | |
 | Jeremiah Day - Geometry - 1839 - 434 pages
...what is the solidity ? Ans. 5040. PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY | OF THE HEIGHT. Let L and... | |
 | J. M. Scribner - Measurement - 1844 - 130 pages
...32552 cubic ft. PROBLEM VIII. To find the Solidity of a Rectangular Prismoid. AKT. 45. Rule. — To the sum of the areas of the two ends add four times...of a section parallel to and equally distant from the parallel ends, and this sum, multiplied by i of the height, will give the solidity. Ex. 1. What... | |
 | William Watson (of Beverley.) - 1845 - 188 pages
...Ans. surf. 1363.4544, sol. 3493.4592. PROBLEM 6. — To find the solidity of a prismoid. RULE. — To the sum of the areas of the two ends, add four times...section parallel to, and equally distant from both ; this sum multiplied by one-sixth of the height, gives the solidity.* EXAMPLES. 1. The length and... | |
 | Scottish school-book assoc - 1845 - 444 pages
...inches? Here 12x8+8 x6=96+48=]44= the sum of the areas of the two ends. Also^^ x— - X 4=10x7x4 = 280= four times the area of a section, parallel to and equally distant from both ends. Therefore (144 + 280) x °B°=424 x 10=4240 is the solidity in solid inches, which is equal to 2'4537... | |
 | 458 pages
...with the result of their project in his behalf." rRODLEM X. To find the solidity of a prismoid. To the sum of the areas of the two ends add four times the area of a section parallel to the two ends and equally distant from them ; and this sum being multiplied by one-sixth of the height,... | |
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