| Shelton P. Sanford - Arithmetic - 1872 - 402 pages
...and write its root for the first figure in the root ; subtract the square number from the left-hand **period, and to the remainder bring down the next period for a** dividend. III. Double the first figure of the root, and write it at the left of tJie dividend for a... | |
| Ezra S. Winslow - Business mathematics - 1872 - 256 pages
...hand period, and place its root in the quotient ; subtract the square of the root from the left hand **period, and to the remainder bring down the next period for a** dividend. 3. Multiply the root so far found — the figure in the quotient — by 2, for a divisor;... | |
| Daniel Barnard Hagar - Algebra - 1873 - 278 pages
...root at the right for the first figure of the required root. Subtract this square from the highest **period, and to the remainder bring down the next period for a** dividend. Divide the dividend, omitting its right-hand order, by twice the root already found, and... | |
| Horatio Nelson Robinson - Algebra - 1874 - 338 pages
...period, and place its root for the first figure of the required root. Subtract the cube from the first **period, and to the remainder bring down the next period for a** dividend. III. At the left of the dividend, write three timen the square of the root already found,... | |
| Horatio Nelson Robinson - Algebra - 1875 - 430 pages
...write its root for the first figure, in the root sought ; subtract the square number from the left-hand **period, and to the remainder bring down the next period for a** dividend. III. At the left of the dividend write twice the first figure of the root, for a trial divisor... | |
| Lorenzo Fairbanks - 1875 - 468 pages
...place its root on the right for the first figure of the root ; subtract the cube from the left-hand **period, and to the remainder bring down the next period for a** dividend. III. Take three times the square of the part of the root already found for a trial divisor.... | |
| George Augustus Walton - 1876 - 358 pages
...period, and write its root as the first term in the answer. Subtract the square number from the left hand **period, and to the remainder bring down the next period for a** dividend. Take twice the root already found for a trial divisor ; rejecting the right hand figure of... | |
| Joseph Ray - Arithmetic - 1877 - 404 pages
...period on the left; place its root on the right, like a quotient in division; subtract the cube from the **period, and to the remainder bring down the next period for a** dividend. 3. Square the root found, and multiply it by 300 for a trial divisor. Find how many times... | |
| Benjamin Greenleaf - Algebra - 1879 - 350 pages
...the left-hand period, and place its root on the right ; subtract the cube of this root from the first **period, and to the remainder bring down the next period for a** dividend. Take three times the square of the root already fonnd, for a trial divisor ; divide the dividend... | |
| Webster Wells - Algebra - 1879 - 468 pages
...left-hand period, and place its root on the right ; subtract the cube of this root from the lefthand **period, and to the remainder bring down the next period for a** div1dend. Divide this dividend, omitting the last two figures, by three times the square of the root... | |
| |