 | Shelton P. Sanford - Arithmetic - 1872 - 402 pages
...and write its root for the first figure in the root ; subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. Double the first figure of the root, and write it at the left of tJie dividend for a... | |
 | Ezra S. Winslow - Business mathematics - 1872 - 256 pages
...hand period, and place its root in the quotient ; subtract the square of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Multiply the root so far found — the figure in the quotient — by 2, for a divisor;... | |
 | Daniel Barnard Hagar - Algebra - 1873 - 278 pages
...root at the right for the first figure of the required root. Subtract this square from the highest period, and to the remainder bring down the next period for a dividend. Divide the dividend, omitting its right-hand order, by twice the root already found, and... | |
 | Horatio Nelson Robinson - Algebra - 1874 - 338 pages
...period, and place its root for the first figure of the required root. Subtract the cube from the first period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend, write three timen the square of the root already found,... | |
 | Horatio Nelson Robinson - Algebra - 1875 - 430 pages
...write its root for the first figure, in the root sought ; subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write twice the first figure of the root, for a trial divisor... | |
 | Lorenzo Fairbanks - 1875 - 468 pages
...place its root on the right for the first figure of the root ; subtract the cube from the left-hand period, and to the remainder bring down the next period for a dividend. III. Take three times the square of the part of the root already found for a trial divisor.... | |
 | George Augustus Walton - 1876 - 358 pages
...period, and write its root as the first term in the answer. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. Take twice the root already found for a trial divisor ; rejecting the right hand figure of... | |
 | Joseph Ray - Arithmetic - 1877 - 404 pages
...period on the left; place its root on the right, like a quotient in division; subtract the cube from the period, and to the remainder bring down the next period for a dividend. 3. Square the root found, and multiply it by 300 for a trial divisor. Find how many times... | |
 | Benjamin Greenleaf - Algebra - 1879 - 350 pages
...the left-hand period, and place its root on the right ; subtract the cube of this root from the first period, and to the remainder bring down the next period for a dividend. Take three times the square of the root already fonnd, for a trial divisor ; divide the dividend... | |
 | Webster Wells - Algebra - 1879 - 468 pages
...left-hand period, and place its root on the right ; subtract the cube of this root from the lefthand period, and to the remainder bring down the next period for a div1dend. Divide this dividend, omitting the last two figures, by three times the square of the root... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... 
