 | George Augustus Walton - Arithmetic - 1864 - 368 pages
...period, and write its root as the first term in the answer. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. Take twice the root already found for a trial divisor ; rejecting the right hand figure of... | |
 | George Augustus Walton - Arithmetic - 1864 - 362 pages
...hand period, and write its root as the first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor.... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Square the root already found, and multiply it by 3 for a trial divisor. Find how many... | |
 | Horatio Nelson Robinson - Algebra - 1866 - 328 pages
...root for the first figure in the required root ; subtract the square of this figure from the first period, and to the remainder bring down the -next period for a dividend. III. Double the root already found, and write the result on the left for a divisor ; find... | |
 | Joseph Ray - Algebra - 1852 - 420 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3rd. Square the root already found, and multiply it by 3 for a trial divisor. Find how many... | |
 | Joseph Ray - Algebra - 1866 - 252 pages
...the right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and place it on the left for a divisor. Find how many times... | |
 | Ezra S. Winslow - Business mathematics - 1867 - 232 pages
...left hand period, and place its root in the quotient; subtract the cube of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Multiply the square of the quotient by 300, for a. divisor; see how many times the divisor... | |
 | Joseph Ray - Arithmetic - 1857 - 360 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3. Square the root found, and multiply it by 300 for a trial divisor. Find how many times... | |
 | Robert Wallace - 1870 - 164 pages
...and place its root to the left, as the first figure of the root ; subtract its square from the first period, and to the remainder bring down the next period for a dividend. Divide this new dividend (excluding the right-hand figure) by twice the first figure of the... | |
 | Benjamin Greenleaf - Arithmetic - 1871 - 350 pages
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend,... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... 
