| George Augustus Walton - Arithmetic - 1864 - 368 pages
...period, and write its root as the first term in the answer. Subtract the square number from the left hand **period, and to the remainder bring down the next period for a** dividend. Take twice the root already found for a trial divisor ; rejecting the right hand figure of... | |
| George Augustus Walton - Arithmetic - 1864 - 362 pages
...hand period, and write its root as the first term in the answer. Subtract the cube from the left hand **period, and to the remainder bring down the next period for a** dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor.... | |
| Joseph Ray - Algebra - 1866 - 420 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left **period, and to the remainder bring down the next period for a** dividend. 3d. Square the root already found, and multiply it by 3 for a trial divisor. Find how many... | |
| Horatio Nelson Robinson - Algebra - 1866 - 328 pages
...root for the first figure in the required root ; subtract the square of this figure from the first **period, and to the remainder bring down the -next period for a** dividend. III. Double the root already found, and write the result on the left for a divisor ; find... | |
| Joseph Ray - Algebra - 1852 - 420 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left **period, and to the remainder bring down the next period for a** dividend. 3rd. Square the root already found, and multiply it by 3 for a trial divisor. Find how many... | |
| Joseph Ray - Algebra - 1866 - 252 pages
...the right, after the manner of a quotient in division. Subtract the square of the root from the left **period, and to the remainder bring down the next period for a** dividend. 3. Double the root already found, and place it on the left for a divisor. Find how many times... | |
| Ezra S. Winslow - Business mathematics - 1867 - 232 pages
...left hand period, and place its root in the quotient; subtract the cube of the root from the left hand **period, and to the remainder bring down the next period for a** dividend. 3. Multiply the square of the quotient by 300, for a. divisor; see how many times the divisor... | |
| Joseph Ray - Arithmetic - 1857 - 360 pages
...period, and place its root on the right, as in division. Subtract the cube of the root from the left **period, and to the remainder bring down the next period for a** dividend. 3. Square the root found, and multiply it by 300 for a trial divisor. Find how many times... | |
| Robert Wallace - 1870 - 164 pages
...and place its root to the left, as the first figure of the root ; subtract its square from the first **period, and to the remainder bring down the next period for a** dividend. Divide this new dividend (excluding the right-hand figure) by twice the first figure of the... | |
| Benjamin Greenleaf - Arithmetic - 1871 - 350 pages
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this **period, and to the remainder bring down the next period for a** dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend,... | |
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