 | Joseph Ray - Arithmetic - 1857 - 348 pages
...its root on the right. like a quotient in division. Subtract the square of this root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the .root found, and place it on the left for a trial divisor. Find how many times... | |
 | Charles Haynes Haswell - Measurement - 1858 - 350 pages
...left-hand period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 332 pages
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend,... | |
 | Horatio Nelson Robinson - Arithmetic - 1859 - 362 pages
...and write its root for the first figure in the required root; subtract the cube from the left hand period, and to the remainder bring down the next period for a/ dividend. III. At the, left of the dividend write three times the square of the first fyurc of the... | |
 | Horatio Nelson Robinson - Arithmetic - 1860 - 444 pages
...and write its root for the first figure in the required root; subtract, the cube from the left hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write three times the square of tlie first figure of the... | |
 | Daniel Adams - Arithmetic - 1861 - 454 pages
...period, and write its root as a quotient in division. Subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... | |
 | Benjamin Greenleaf - Arithmetic - 1861 - 338 pages
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. RULE. — Separate the given number into as many periods as possible of three figures each,... | |
 | John Flint (inspector of schools.) - 1862 - 152 pages
...period, and write its cube root as the first figure of the root. Subtract its cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the part of the root found by 300 for a trial divisor ; divide the... | |
 | Benjamin Greenleaf - 1863 - 338 pages
...the left-hand period, and place its root on the right ; subtract the cube of this root from the first period, and to the remainder bring down the next period for a dividend. At the left of the dividend write three times the square ofth* root already found, for a... | |
 | Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...wríte its root for the first figure in the root sought ; subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write twice the first figure, of the root, for a trial divisor... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... 
