| Joseph Ray - Arithmetic - 1857 - 348 pages
...its root on the right. like a quotient in division. Subtract the square of this root from the left **period, and to the remainder bring down the next period for a** dividend. 3. Double the .root found, and place it on the left for a trial divisor. Find how many times... | |
| Charles Haynes Haswell - Measurement - 1858 - 350 pages
...left-hand period, and place its root in the quotient ; subtract the square number from the left-hand **period, and to the remainder bring down the 'next period for a** new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 332 pages
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this **period, and to the remainder bring down the next period for a** dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend,... | |
| Horatio Nelson Robinson - Arithmetic - 1859 - 362 pages
...and write its root for the first figure in the required root; subtract the cube from the left hand **period, and to the remainder bring down the next period for a/** dividend. III. At the, left of the dividend write three times the square of the first fyurc of the... | |
| Horatio Nelson Robinson - Arithmetic - 1860 - 444 pages
...and write its root for the first figure in the required root; subtract, the cube from the left hand **period, and to the remainder bring down the next period for a** dividend. III. At the left of the dividend write three times the square of tlie first figure of the... | |
| Daniel Adams - Arithmetic - 1861 - 454 pages
...period, and write its root as a quotient in division. Subtract the square number from the left-hand **period, and to the remainder bring down the next period for a** dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... | |
| Benjamin Greenleaf - Arithmetic - 1861 - 338 pages
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this **period, and to the remainder bring down the next period for a** dividend. RULE. — Separate the given number into as many periods as possible of three figures each,... | |
| John Flint (inspector of schools.) - 1862 - 152 pages
...period, and write its cube root as the first figure of the root. Subtract its cube from the left hand **period, and to the remainder bring down the next period for a** dividend. Multiply the square of the part of the root found by 300 for a trial divisor ; divide the... | |
| Benjamin Greenleaf - 1863 - 338 pages
...the left-hand period, and place its root on the right ; subtract the cube of this root from the first **period, and to the remainder bring down the next period for a** dividend. At the left of the dividend write three times the square ofth* root already found, for a... | |
| Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...wríte its root for the first figure in the root sought ; subtract the square number from the left-hand **period, and to the remainder bring down the next period for a** dividend. III. At the left of the dividend write twice the first figure, of the root, for a trial divisor... | |
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