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" Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained... "
The American Tutor's Assistant Revised, Or, A Compendious System of ... - Page 150
by Zachariah Jess - 1810 - 210 pages
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The Juvenile Arithmetick, and Scholar's Guide: Illustrated with Familiar ...

Martin Ruter - Arithmetic - 1831 - 190 pages
...in the left hand period, place the root of it in the quotient, subtract the cube from the left hand period, and to the remainder bring down the next period for a resolvend. 3. Square the quotient and multiply the square by 3 for a defective divisor. 4. Seek how...
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The Youth's Assistant in Theorhetic [sic] and Practical Arithmetic: Designed ...

Zadock Thompson - Arithmetic - 1832 - 186 pages
...cube in the left hand period, and place its root in the quotient. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the quotient by 300, calling it the triple square, and the quotient...
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The Arithmetical Manual

Samuel Read Hall - Arithmetic - 1832 - 294 pages
...highest figure in the root required. Subtract the square of the root already found from the left hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor ; seek how many times the divisor is contained...
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The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for ...

Zadock Thompson - Arithmetic - 1832 - 186 pages
...highest figure in the root required. Subtract the square of the root already found from the left hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor; seek how many times the divisor is contained...
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Adam's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - Arithmetic - 1833 - 268 pages
...period, and write its root as a quotient in division. Subtract the square number.from the left hand period, and to the remainder bring down the next period for a dividend. . III. Double the root already found for a divisor ; seek how many times the divisor is contained...
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The North American Arithmetic: Part Third, for Advanced Scholars, Volume 3

Frederick Emerson - Arithmetic - 1834 - 300 pages
...hand period, and write its root in the quotient. Subtract the square of this root from the left hand period, and to the remainder bring- down the next period for a dividend. Thirdly — Double the root already found, for a divisor. Ascertain how many times the divisor...
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The New System of Practical Arithmetic: Whereby Most of the Various Problems ...

Charles Potts - Arithmetic - 1835 - 202 pages
...hand period, and set its root on the right of the given number ; subtract said cube from the left hand period, and to the remainder bring down the next period for a dividual. 3. Square the root, and multiply the square by 3 for a defective divisor. 4. Reserve, mentally, the...
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The Teachers' Assistant: Or a System of Practical Arithmetic

Stephen Pike - Arithmetic - 1835 - 210 pages
...period, and set its root on the right of the given number: subtract said square from the left hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and try hp\v often this divisor (with the figure used in the trial...
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The Western Arithmetic: Or, Pennsylvania and Ohio Accomptant: Being a Plain ...

James L. Connolly (mathematician.) - Arithmetic - 1835 - 264 pages
...not too great, of the first period, for the first figure of your root, subtract its cube from said period, and to the remainder bring down the next period for a resolvend. Take three times the square of the root for a defective divisor, and seek how often it is...
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A brief compendium of arithmetic

Benjamin Snowden - 1835 - 108 pages
...and put its root for the first figure of the root sought. 2. — Subtract this cube from the first period, and to the remainder bring down the next period for a dividend. 3. — Find a divisor by multiplying the square of the root by 300. 4. — Divide the dividend...
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