 | Mathematics - 1801 - 658 pages
...r-tgular polygon, :• ' - .. • RIJ.LE. -i.*.. . .T Multiply the perimeter of the figure, or sum of itl sides, by the perpendicular falling from its centre...its sides, and half the product will be the area. RULE * DEMONSTRATION. Every regular polygon is composed of as many equal triangles as it has sides,... | |
 | Samuel Webber - Mathematics - 1808 - 466 pages
...triangle GCD. 4*4 2'3 132 88 10'12 PR0BLEM VII. To find the area of a regular polygon* • RULE 1.* ^ Multiply the perimeter of the figure, or sum of its...its sides, and half the product will be the area. RULE 2.f Square the side of the polygon ; multiply that square by the multiplier, set opposite to its... | |
 | John Nicholson - Machinery - 1825 - 822 pages
...nb 4 ke. 2 mf 3 6 7 df. 6 CR 10 2)36 2)70 18 contents. 35 contents. 18 contents dc fe 35 — — cf ab 53 contents of the irregular — polygon. Prob....the arc AD, and the diameter, or the radius AC or CDgiven, to find the others. If any two of these lines be given, two sides of one of the rightangled... | |
 | John Nicholson - Machinery - 1825 - 838 pages
...content«. 18 conteuts. 18 contents dc fe 35 — cf ab 53 contents of the irregular — polys00Prob. 7. To find the Area of a Regular Polygon. Rule. Multiply...and half the product will be the area. Prob. 8. In a Circnlar Arc, having any two of the following lines, viz. the chord AB, the versed sine DP, the chord... | |
 | John Nicholson (civil engineer.) - Great Britain - 1825 - 1008 pages
...contents. 35 contenti. 18 contents d. cfe 35 — — cf ab 53 contents of the irregular — polygon. Prol. 7. To find the Area of a Regular Polygon. Rule. Multiply...its sides, and half the product will be the area. Prod. 8. In a Circular Arc, having any two of the following lines, viz. the chord AB, the versed sine... | |
 | William Watson (of Beverley.) - 1845 - 188 pages
...regular polygon. RULE. — Multiply the sum of the sides by the perpendicular demitted from its centre to one of its sides, and half the product will be the area. 2. — Multiply the square of one side by the number or area opposite to the name of the polygon in... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...PROBLEM XVI. To find the area of a regular polygon. RULE. Multiply half the perimeter of the figure by the perpendicular falling from its centre upon one of its sides, and the product will be the area. EXAMPLES. 2. What is the area of a hexagon, whose side is 16J feet, anil... | |
 | Robert Stuart - Architecture - 1854 - 1272 pages
...nb 4 mf 3 6 df._6 2)36 . 18 content. 10 2)70" 35 content. 18 content dcfe 35 content cfab 53 content of the irregular polygon. Prob. 7. To find the area...sides, and half the product will be the area. Prob. ОТ In a circular arc, having any two of the following lines viz. the chord AB, the versed sine DP,... | |
 | Lorenzo Fairbanks - 1875 - 472 pages
...NOTES. — 1. The area of a regular polygon is equal to half the product of the perimeter, or sum of all its sides, by the perpendicular falling from its centre upon one of the sides. 2. The perimeters of all similar figures are proportional to any homolo gous lines, and... | |
 | Simpson Bolland - Iron-founding - 1893 - 420 pages
...the sum of the sides or perimeter of the polygon by the perpendicular, demitted from its centre to one of its sides, and half the product will be the area. Example. — Required the weight of a casting, in iron, having the form of a regular hexagon ABCDEF,... | |
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Sides 5 6 7 8 9 10 To find the area of a polygon: Multiply the sum of the sides (perimeter of the polygon) by the perpendicular dropped from its center to one of its sides, and half the product will be the area. This rule applies to all regular polygons.... 
