 | Thomas Hornby (land surveyor.) - Surveying - 1827 - 318 pages
...each side from that half sum ; then multiply the said half sum and the three remainders continually together ; and the square root of the product will be the area of the triangle. EXAMPLES. 1. — Required the area of the triangular field ABC, whose base AB is 650,... | |
 | Thomas Curtis - Aeronautics - 1829 - 810 pages
...sides, subtract each side separately, and multiply the half sum and the three remainders continually together; and the square root of the product will be the area. the sides Then by hence AD r: — E 1C, geAC, and AB, t» — «' "~~ 2 с ¿> — ; o AD —DB = —... | |
 | John Bonnycastle - Geometry - 1829 - 256 pages
...— c2) X (c2— a— 56 MENSURATION 2. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. EXAMPLES. 1. Required the area of the triangle ABC, whose three sides BC, CA, and AB are... | |
 | John Armstrong - Arithmetic - 1831 - 152 pages
...three sides subtract each side severally. 2. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. RULE. ii. Any two sides of a triangle being multiplied together, and the product again by... | |
 | Ira Wanzer - Arithmetic - 1831 - 408 pages
...subtract each side separately ; then multiply the said half sum and the three remainders continually together, and the square root of the product will be the area of the triangle. Ex. 1. What is the area of a triangle whose base is 15 feet, and perpendicular height... | |
 | George Alfred - Arithmetic - 1834 - 336 pages
...sides subtract each side several! y, then multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. AN EXAMPLE. In the triangle ABC let the side AC be 40 poles, CB50, and AB 60 ; required,... | |
 | John M'Nevin - Arithmetic - 1841 - 300 pages
...sum, subtract each side severally; from the half sum multiply the half sum and the three differences together, and the square root of the product will be the area. 1. Required the area of a right angled triangle whose base is 40 and perpendicular 30 perches? Ans.... | |
 | John M'Nevin - Arithmetic - 1841 - 300 pages
...sum, subtract each side severally; from the half sum multiply the half sum and the three differences together, and the square root of the product will be the area. 1. Required the area of a right angled triangle whose base is 40 and perpendicular 30 perches? Ans.... | |
 | William Watson (of Beverley.) - 1845 - 188 pages
...crooked fence, so as to include as much on one side as they exclude on the other. remainders continually together, and the square root of the product will be the area. EXAMPLES. I . Required the area of a triangle, the sides of which are 26, 28, and 30. 26 28 42 42 42... | |
 | 458 pages
...sides subtract each side severally, then multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. 1. What will be the area of the triangle AB c, the side of which, AB, is 50 ft., B c 40 ft.,... | |
| |
Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required... 
