 | Abel Flint - Surveying - 1804 - 226 pages
...third Remainder, 13 - .1.11394 The Square of the Area, 31000 4.49179 Area 176 Square Chains - 2.24589. RULE 4. When two Sides of a Triangle and their contained...between them 28° 5'. Demanded the Area. One Side, 105 2.02119 The other Side, 85 - - 1.92942 Sine Angle, 28° 5' - - 9.67280 13.62341 Subtract Radius - -... | |
 | Abel Flint - Surveying - 1808 - 190 pages
...third Remainder, 13 - 1.11394 The Square of the Area, 310CO 4.49179 Area 176 Square Chains - 2.24589 RULE 4. When two Sides of a Triangle and their contained...between them 28° 5'. Demanded the Area. One Side, 105 - - - 2.02119 The other Side, 85 - - 1.92942 Sine Angle, 28° 5' •- - 9.67280 13.62341 Subtract Radius... | |
 | Abel Flint - Deeds - 1818 - 184 pages
...third Remainder, 13 -- 1.11394 The Square of the Area, 31000 4.49179 Area 176 Square Chains - 2.24589 RULE 4. When two Sides of a Triangle and their contained...EXAMPLE. Suppose a Triangle one of whose Sides is 1 05 Rods and another 85, and the Angle contained between them 28° 5'. Demanded the Area. One Side,... | |
 | Abel Flint - Surveying - 1825 - 252 pages
...contained Angle, that is, the Angle made by those Sides, are given, the Area may be found aa follows 1 Add together the Logarithms of the two Sides and the...another 85, and the Angle contained between them 28° 5e. Demanded the Area. One Side, 105 - - . - 2.02119 The other Side, 85 ... 1.92942 Sine Angle, 28°... | |
 | Abel Flint - Surveying - 1830 - 322 pages
...The square of the area, 31030.083 nearly 4.491796 Area 176 square chains 150 square links 2.245893 RULE 4. When two sides of a triangle and their contained...logarithmic sine of the angle ; from their sum subtract the lo. garithm of radius, the remainder will be the logarithm of double the area. EXAMPLE. Suppose a triangle... | |
 | Adrien Marie Legendre - Geometry - 1836 - 394 pages
...altitude 25£ feet. Ans. 68.736] CASK II When two sides and their included angle are given. RULE. — Add together the logarithms of the two sides and the logarithmic sine of their included angle ; from this sum subtract the logarithm of the radius, which is 1 0, and the remainder... | |
 | Charles Davies - Navigation - 1837 - 342 pages
...altitude 9.67 chains? Ms. ~iA iR 38 P, SECOND METHOD. Measure two sides and their included angle. Then, add together the logarithms of the two sides and the logarithmic sine of their included angle ; from this sum subtract the logarithm of the radius, which is 10, and the remainder... | |
 | Charles Davies - Surveying - 1839 - 376 pages
...altitude 9.67 chains 1 Ans. lA iR 38 P SECOND METHOD. Measure two sides and their included angle. Then, add together the logarithms of the two sides and the logarithmic sine of their included angle ; from this sum subtract the logarithm of the radius, which is 10, and the remainder... | |
 | Charles Davies - Surveying - 1839 - 376 pages
...altitude 9.67 chains 1 JSns. lA iR 38 P SECOND METHOD. x Measure two sides and their included angle. Then, add together the logarithms of the two sides and the logarithmic sine of their included angle ; from this sum subtract the logarithm of the radius, which is 10, and the remainder... | |
 | Charles Davies - Navigation - 1841 - 414 pages
...altitude 9.67 chains 1 Ans. lA iR 38 P SECOND METHOD. Measure two sides and their included angle. Then, add together the logarithms of the two sides and the logarithmic sine of their included angle ; from this sum subtract the logarithm of the radius, which is 10, and the remainder... | |
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... radius, which is 10, and the remainder will be the logarithm of double the area of the triangle. Find, from the table, the number answering to this logarithm, and divide it by 2 ; the quotient will be the required area (Geom. 
