 | Abel Flint - Surveying - 1804 - 226 pages
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then multiply the Base by half the Perpendicular, or the Perpendicular by half the Base ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the Product will... | |
 | Robert Gibson - Surveying - 1806 - 486 pages
...thence complete the parallelogram. PROBLEM VI. To find the content of a triangular piece of ground. Multiply the base by half the perpendicular, or the perpendicular by half the base; or take half the product of the base into the perpendicular. The reason hereof is plain, from cor.... | |
 | Abel Flint - Surveying - 1808 - 190 pages
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then multiply the Base by half the Perpendicular, or the Perpendicular by half the Base ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the Product will... | |
 | Robert Gibson - 1808 - 482 pages
...parallelogram. 182 To find the Content of Ground. PROB. VI. To find the content of a triangular piece of ground, Multiply the base by half the perpendicular, or the perpendicular by half the base ; or take half the product of the base into the perpendicular. The reason hereof is plain, from cor.... | |
 | Nicolas Pike - Algebra - 1808 - 470 pages
...and scale, as in die last figure. Ans. 160-05 feet. ART. 6. To measure a Triangle. RULE — If it be a right angled triangle, multiply the base by half the perpendicular, or half the base by the perpendicular, and die product will be the area : but if it be an oblique angled... | |
 | Robert Gibson - Surveying - 1811 - 580 pages
...thence completing the parallelogram. PROB. VI To find the content of a triangular piece of ground. Multiply the base by half the perpendicular, or the perpendicular by half the base ; or take half the product of the base into the perpendicular. The reason of this is plain, from cor.... | |
 | Abel Flint - Surveying - 1813 - 214 pages
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base; then multiply the Base by half the Perpendicular, or the Perpendicular by half the Base; the Pro. duct will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the Product... | |
 | Robert Gibson - Surveying - 1814 - 558 pages
...thence completing the parallelogram. PROB. VI. To find the content of a triangular fiiece of ground. Multiply the base by half the perpendicular, or the perpendicular by half the base ; or take half the product of the base into the perpendicular. The reason of this is plain, from cor.... | |
 | Robert Gibson - Surveying - 1818 - 502 pages
...and thence complete the parallelogram. PROB. VI. To find the content of a triangular piece of ground. Multiply the base by half the perpendicular, or the perpendicular by half the base ; or take half the product of the base into the perpendicular. The reason hereof is plain, from cor.... | |
 | Anthony Nesbit, W. Little - Measurement - 1822 - 916 pages
...quotients will be the area in ale and wine gallons, ain malt-bushels. Nile. If the base be multiplied by half the perpendicular, or the perpendicular by half the base, the product will be the area in iqiiara inches. EXAMPLES. 1. Required the area of the triangle ABC, in ale and... | |
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Base ; then multiply the Base by half the Perpendicular, or the Perpendicular by half the Base ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the Product will be the Area. 
