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" RULE. Divide the given interest by the interest of $1 for the given time and rate, and the quotient will be the principal. "
Burnham's Arithmetic, Revised: A New System of Arithmetic, on an Improved ... - Page 198
by Charles Guilford Burnham - 1857 - 324 pages
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A New System of Arithmetic, on the Cancelling Plan: Embracing the Rules of ...

Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...above we derive the following RULE : To find the Present Worth. DIVIDE the given sum by the amount of $1 for the given time, and the quotient will be the present worth. The present wort h subtracted from the debt, will leave the discount. 2. What is the...
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Higher Arithmetic: Designed for the Use of High Schools, Academies, and Colleges

George Roberts Perkins - Arithmetic - 1841 - 274 pages
...per cent., and the interest, to find the principal. By the reverse of the last problem we obtain this RULE. Divide, the given interest by the interest of $1, for the given time, and given rate per cent. Examples. 1. The interest on a certain principal, for 9 months and 10 days,at...
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A New System of Arithmetic, on the Cancelling Plan: Embracing the Rules of ...

Charles Guilford Burnham - Arithmetic - 1841 - 324 pages
...the above we derive the following RULE: To find the present worth. Divide the given sum by the amount of $1 for the given time, and the quotient will be the present worth. The present worth, subtracted from the debt, will leave the discount. 2. What is the...
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Engineers' and Mechanics' Pocket-book ...

Charles Haynes Haswell - Engineering - 1844 - 298 pages
...compound interest. DISCOUNT. The Time, Rate per Cent., and Interest being gieen, to find the Principat. RULE.— Divide the given interest, by the interest of $1, for the given rate and time. EXAMPLE.— What sum of money at 6 per cent, will in 14 months gain $14 ? $14H-.07 =...
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An Elementary Arithmetic ...: Serving as an Introduction to the Higher ...

George Roberts Perkins - Arithmetic - 1846 - 266 pages
...cent., and the interest, to find the principal. By the reverse of the last problem, we obtain this RULE. Divide the given interest by the interest, of $1, for the given time, and given rate per cent. EXAMPLES, 1. The interest on a certain principal, for 9 months and 10 days, at...
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Practical Arithmetic, Uniting the Inductive with the Synthetic Mode of ...

James Bates Thomson - Arithmetic - 1846 - 402 pages
...interest by this fraction ; (Art. 141 ;) and the quotient will be the principal required. Or, simply divide the given interest by the interest of $1 for the given time and rate expressed in decimals ; and the quotient will be the principal. 12. What sum put at interest will...
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Higher Arithmetic: Or, The Science and Application of Numbers; Combining the ...

James Bates Thomson - Arithmetic - 1847 - 426 pages
...interest. Hence, 423. To find the principal, when the interest, rate per cent., and time are given. Divide the given interest by the interest of $1 for the given time and rate, expressed in decimals ; and the quotient will be the principal required. Or, make the interest...
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Higher Arithmetic; Or, The Science and Application of Numbers: Combining the ...

James Bates Thomson - Arithmetic - 1848 - 434 pages
...interest. Hence, 423. To find the principal, when the interest, rate per cent., and time are given. Ijivide the given interest by the interest of $1 for the given time and rate, expressed in decimals ; and the quotient will be the principal required. Or, make the interest...
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An Elemtary Arithmetic ...: Serving as an Introduction to the Higher ...

George Roberts Perkins - Arithmetic - 1849 - 346 pages
...than the interest on $1, as the given sum is times greater than $1. Hence, •we have the following RULE. Divide the given interest by the interest of $1, for the given time, and given rate per cent. EXAMPLES. 1. The interest on a certain principal, for 9 months and 10 days, at...
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Higher Arithmetic: Designed for the Use of High Schools, Academies, and ...

George Roberts Perkins - Arithmetic - 1849 - 344 pages
...cent., and the interest, to find the principal. By the reverse of the last problem, we obtain this RULE. Divide the given interest by the interest of $1 for the given time and given rate per cent.; and the quotient will be the number of dollars in the principal. EXAMPLES. 1....
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