 | Richard Turner - Geometry - 1787 - 264 pages
...another. BC That is, the Parallelogram ABCD is equal to the Parallelogram BEF C. Note. Triangles on the fame Bafe, and between the fame Parallels, are equal ; becaufe they are Half the circumfcribing Parallelograms. Note alfo, that Triangles and Parallelograms having the fame... | |
 | John Playfair, Euclid - Circle-squaring - 1804 - 468 pages
...the parallelogram ABCD is equal to EFGH. Wherefore, parallelograms, &.c. QK ED PROP. XXXVII. THE OR. TRIANGLES upon the fame bafe, and between the fame parallels, are equal to one another. Let the triangles ABC, DBC be upon the fame bafe BC, and between the fame pa- T, A... | |
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Triangles on the fame Bafe, and between the fame Parallels, are equal ; becaufe they are Half the circumfcribing Parallelograms. 