| Benjamin Martin - Mathematics - 1736 - 360 pages
...IH HG : HG EG :ED. EG : ED. X>. £. D. Theorem- XXX. In any plain Triangle, as the Bafe or Icngeft **Side is to the Sum of the other two Sides ; So is the Difference** of thofe Sides, to the Difference of the Segments of the Bafe. Demouftration. In the Triangle > GBD,... | |
| John Potter - Mathematics - 1753 - 395 pages
...unknown Angles. Rule 3. When the three Sides are given to find the Angles. As the Bafe of any Triangle **Is to the Sum of the other two Sides, So is the Difference** of thofe Sides To the Difference of the two Segments of the Bafe, made by Jetting fall a Perpendicular... | |
| Richard Cockrel - 1792 - 146 pages
...* t a"1 *. f • V" I w *» : tL *. . i.fc. * . . ' . _ ^.s. .~.n ". As the Bafe or largeft Slot ' **Is to the Sum of the other two Sides So is the Difference** 'of thofe Sides To the Difference oif"th"d Segments of the Bale, made by a Perpendicular let fall from... | |
| Mathematics - 1801 - 658 pages
...whole triangle iuto two right-angled triangles j, it will be As the base, or sum of the segments : **Is to the sum of the other two sides : : So is the difference** of those sides : To the difference of the segments of the base.* Then \ * J)EMON STRATIOH. From one... | |
| John Bonnycastle - Trigonometry - 1806 - 464 pages
...three sides are given, to find the angles; RULE. '/s 19 Then, as the base, or sum of its segments, **is to the sum of the other two sides, so is the difference** of those sides to the difference of the segments of the base. And half this difference, being added... | |
| Charles Hutton - Mathematics - 1807
...two right-angled triangles : then the; proportion will be, As As the "base, or sums of the segments, **Is to the sum of the other two sides; So is the difference** of those sides, To the diff. of the segments of the base. Then take half this difference of the segments,... | |
| Abel Flint - Geometry - 1808 - 192 pages
...maybe found by CASE I or II. CASE IV. The three Sides given to find the Angles. Fig. 50. The solution **of this CASE depends on the following PROPOSITION.....between these Segments, added to half the Sum of the** S§gments, that is to half the length of the longest Side, will give the greatest Segment ; and this... | |
| Nicolas Pike - Algebra - 1808 - 468 pages
...given, to find tlx Angles. RULE 3. — As the base of any triangle (or sum of the segments of the base) **is to the sum of the other two sides : so is the difference** of • those sides, to the difference of the two segments of the base, made by letting fall a perpendicular... | |
| Charles Hutton - Mathematics - 1811
...into two right-angled triangles : then the proportion will be, As As the base, or sum of the segments, **Is to the sum of the other two sides; So is the difference** o£ those sides, To the diff. of the segments of the base. Then take half this difference of the segments,... | |
| John Gummere - Surveying - 1817 - 206 pages
...and the whole triangle into two right angled triangles. Then, As the base, or sum of the segments, **Is to the sum of the other two sides ; , . So is the difference** of those sides, To the difference of the segments of the base.* * DEMONSTRATION. Let ABC, Fig. 48,... | |
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