 | Benjamin Martin - Mathematics - 1736 - 360 pages
...IH HG : HG EG :ED. EG : ED. X>. £. D. Theorem- XXX. In any plain Triangle, as the Bafe or Icngeft Side is to the Sum of the other two Sides ; So is the Difference of thofe Sides, to the Difference of the Segments of the Bafe. Demouftration. In the Triangle > GBD,... | |
 | John Potter - Mathematics - 1753 - 395 pages
...unknown Angles. Rule 3. When the three Sides are given to find the Angles. As the Bafe of any Triangle Is to the Sum of the other two Sides, So is the Difference of thofe Sides To the Difference of the two Segments of the Bafe, made by Jetting fall a Perpendicular... | |
 | Richard Cockrel - 1792 - 146 pages
...* t a"1 *. f • V" I w *» : tL *. . i.fc. * . . ' . _ ^.s. .~.n ". As the Bafe or largeft Slot ' Is to the Sum of the other two Sides So is the Difference 'of thofe Sides To the Difference oif"th"d Segments of the Bale, made by a Perpendicular let fall from... | |
 | Mathematics - 1801 - 658 pages
...whole triangle iuto two right-angled triangles j, it will be As the base, or sum of the segments : Is to the sum of the other two sides : : So is the difference of those sides : To the difference of the segments of the base.* Then \ * J)EMON STRATIOH. From one... | |
 | John Bonnycastle - Trigonometry - 1806 - 464 pages
...three sides are given, to find the angles; RULE. '/s 19 Then, as the base, or sum of its segments, is to the sum of the other two sides, so is the difference of those sides to the difference of the segments of the base. And half this difference, being added... | |
 | Charles Hutton - Mathematics - 1807
...two right-angled triangles : then the; proportion will be, As As the "base, or sums of the segments, Is to the sum of the other two sides; So is the difference of those sides, To the diff. of the segments of the base. Then take half this difference of the segments,... | |
 | Abel Flint - Geometry - 1808 - 192 pages
...maybe found by CASE I or II. CASE IV. The three Sides given to find the Angles. Fig. 50. The solution of this CASE depends on the following PROPOSITION.....between these Segments, added to half the Sum of the S§gments, that is to half the length of the longest Side, will give the greatest Segment ; and this... | |
 | Nicolas Pike - Algebra - 1808 - 468 pages
...given, to find tlx Angles. RULE 3. — As the base of any triangle (or sum of the segments of the base) is to the sum of the other two sides : so is the difference of • those sides, to the difference of the two segments of the base, made by letting fall a perpendicular... | |
 | Charles Hutton - Mathematics - 1811
...into two right-angled triangles : then the proportion will be, As As the base, or sum of the segments, Is to the sum of the other two sides; So is the difference o£ those sides, To the diff. of the segments of the base. Then take half this difference of the segments,... | |
 | John Gummere - Surveying - 1817 - 206 pages
...and the whole triangle into two right angled triangles. Then, As the base, or sum of the segments, Is to the sum of the other two sides ; , . So is the difference of those sides, To the difference of the segments of the base.* * DEMONSTRATION. Let ABC, Fig. 48,... | |
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As the base or sum of the segments Is to the sum of the other two sides, So is the difference of those sides To the difference of the segments of the base. 
