VI. To find the content of a triangular piece of ground, Multiply the base by half the perpendicular, or the perpendicular by half the base ; or take half the product of the base into the perpendicular. The reason hereof is plain, from cor. A Treatise of Practical Surveying, ... - Page 182by Robert Gibson - 1808 - 440 pagesFull view - About this book
| Robert Gibson - Surveying - 1795 - 384 pages
...thereof • to that of the Bafe, by a Right Line, and thence compleat the Parallelogram. PROB. PR 0 S. VI. To find the Content of a «Triangular Piece of Ground. Multiply the Bafe by Half the Perpendicular, or the Perpendicular by Half the Bafe ; or take Half the Product of... | |
| Abel Flint - Surveying - 1804 - 226 pages
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then multiply the Base by half the Perpendicular, or the Perpendicular by half the Base ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the... | |
| Abel Flint - Surveying - 1808 - 190 pages
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then multiply the Base by half the Perpendicular, or the Perpendicular by half the Base ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the... | |
| Robert Gibson - Surveying - 1811 - 580 pages
...the extremity thereof to that of the base by a right line, and thence completing the parallelogram. PROB. VI To find the content of a triangular piece...product of the base into the perpendicular. The reason of this is plain, from cor. 2. theo. 12. eeom. EXAMPLE. PL. 1. Jig. 16. Let ^U^ be a triangular piece... | |
| Robert Gibson - Surveying - 1814 - 558 pages
...line, and thence completing the parallelogram. PROB. VI. To find the content of a triangular fiiece of ground. Multiply the base by half the perpendicular,...product of the base into the perpendicular. The reason of this is plain, from cor. 2. theo. 12. geom. EXAMPLE. PL. i.Jig. 16. Let ABC be a triangular piece... | |
| Robert Gibson - Surveying - 1818 - 502 pages
...the extremity thereof to that of the base, by a right line ; and thence complete the parallelogram. PROB. VI. To find the content of a triangular piece...perpendicular. The reason hereof is plain, from cor. 2. theo, \3.. sect. i. EXAMPLE. D Let ABC be a triangular piece of ground, whose longest side or base BC, is... | |
| Robert Gibson - Surveying - 1821 - 594 pages
...1 : SZ-A : ; DAXAB ; 8. ^ JxVAXJIi=tke area of the parallelogram. Q. /.s I» , . 9 PROB. VI. Tafnd the content of a triangular piece of ground. Multiply...product of the base into the perpendicular. The reason of this is plain, from cor. 2. theo. 12. geom. EXAMPLE. PL. 1. 2ig. 16. Let ABC be a triangular piece... | |
| Anthony Nesbit - Surveying - 1824 - 476 pages
...are given. RULE. Multiply the base by the perpendicular, and half the product will be the area. Or, multiply the base by half the perpendicular ; or the perpendicular by half the base, and the product will be the area. Aote 1. If double the area of a triangle be divided by one of its... | |
| Abel Flint - Surveying - 1825 - 252 pages
...Drop a Perpendicular from one of the Angles to its opposite Side, which may be called the Base ; then multiply the Base by half the Perpendicular, or the Perpendicular by half the Base ; the Product will be the Area. Or, multiply the whole Base by the whole Perpendicular, and half the... | |
| James Hale - Surveying - 1829 - 124 pages
...? Ans. 63x28=1764-r-160=11 Acres 4 Rods. PROBLEM III. To find the Area of a Right Angled Triangle. Multiply the Base by half the Perpendicular, or the Perpendicular by half the Base, the Product is the Area; or, multiply the Base and Pe/pendicular together, and half the Product is... | |
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